4 years ago

Identifying products resulting in a difference of squares

Mathematics

1 answer:

Svetlanka [38]4 years ago

3 0

Correct answers are 2d and 4th

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What is the gcf of 48m^5n and 81m^2n^2

JulijaS [17]

Answer:

gcf is $3m^2n$

Step-by-step explanation:

we are given

$48m^5n$ and $81m^2n^2$

Firstly, we will find factors of both expression

$48m^5n=2\times 2\times2\times 2\times 3\times m^2\times m^3\times n$

$81m^2n^2=3\times 3\times 3\times 3\times m^2\times n\times n$

now, we will find common factors among them

we can see that

For finding gcf, we always find common factors

so,

common terms are 3,m^2 and n

so, gcf is

$=3\times m^2\times n$

$=3m^2n$

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