Answer:
The answer is below.
Explanation:
The z score is a used in statistics to determine by how many standard deviations the raw score is above or below the mean. The z score is given by:
a) Given that n = 100, μ = 2000, σ = 18
For x < 1995 millimeters:
From the normal distribution table, P(x < 1995) = P(z < -2.78) = 0.0027
b) P(z > z*) = 10% = 0.1
P(z < z*) = 1 - 0.1 = 0.9
z* = 1.28
From the normal distribution table, P(z < z
Answer:
Please consider the following explanation.
Explanation:
Bob is correct in this case as Penny didn't make a claim that the goods were non-conforming. Penny is incorrect. Since there was no claim of non conformance, Bob doesn't have to refund the $3.000.
Answer:
a) II only
Explanation:
Bonita is planning to join the new company because there is an availability of getting a loan from the company. Unlike her previous employer, the new employer has different packages for employees such as retirement plans as well as the available of loans for employee. Therefore, it can be concluded that the correct option is a.
Answer: D. Search, Display, Video, Shopping and App
Explanation: Advertising with Google Ads starts with creating a campaign based on your business objectives. Each campaign type determines where your ads appear and the format in which those ads are displayed. Different campaign types — Search, Display, Video, Shopping, and App — can support your business objectives.
Answer:
The amount in the account on the 18th birthday = $ 25,645.41
Explanation:
<em>The investment can be described as an ordinary annuity. An ordinary annuity is a series of equal periodic cash flows that occur for a certain number of years</em>
<em>The amount the invest will accrue principal plus interest is known as the f</em><u><em>uture value</em></u><em> of the annuity</em>
It is determined as follows:
<em>FV = A × ( (1+r)^n -1 ) / r</em>
FV - ?, A = 1000. r - 4%- 0.04, n - 18
FV = 1,000× ( ( (1.04)^(18) - 1 )/ 0.04
= 1,000 × 25.64541288
= $ 25,645.41
The amount in the account on the 18th birthday = $ 25,645.41