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katen-ka-za [31]
2 years ago
15

What is the value of z?

Mathematics
2 answers:
qwelly [4]2 years ago
8 0

Answer:

The value of the z-score tells you how many standard deviations you are away from the mean. If a z-score is equal to 0, it is on the mean. A positive z-score indicates the raw score is higher than the mean average. For example, if a z-score is equal to +1, it is 1 standard deviation above the mean

Licemer1 [7]2 years ago
6 0

Answer:

z = 23 degrees

Step-by-step explanation:

Total degree inside a triangle = 180

We can add up the 2 angles we got.

62 + 95 = 157

Subtract 157 from 180.

180 - 157 = 23

Check = the angle missing is an acute angle (less than 90 degrees) and 23 is less than 90 degrees so it is possible.

I hope this helped and please mark me as brainliest!

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Which statement describes the inverse of m(x) = x2 – 17x?
stealth61 [152]

Answer:

The correct option is;

The \ domain \ restriction \ x \geq \dfrac{17}{2} \ results \ in \ m^{-1}(x) = \dfrac{17}{2} \pm \sqrt{x + \dfrac{289}{4} }}

Step-by-step explanation:

The given information is that m(x) = x² - 17·x

The above equation can be written in the form;

y = x² - 17·x

Therefore;

0 = x² - 17·x - y

From the general solution of a quadratic equation, 0 = a·x² + b·x + c we have;

x = \dfrac{-b\pm \sqrt{b^{2}-4\cdot a\cdot c}}{2\cdot a}

By comparison to the equation,0 = x² - 17·x - y, we have;

a = 1, b = -17, and c = -y

Substituting the values of a, b and c into the formula for the general solution of a quadratic equation, we have;

x = \dfrac{-(-17)\pm \sqrt{(-17)^{2}-4\times (1) \times (-y)}}{2\times (1)} = \dfrac{17\pm \sqrt{289+4\cdot y}}{2}

Which can be simplified as follows;

x =  \dfrac{17\pm \sqrt{289+4\cdot y}}{2}= \dfrac{17}{2} \pm \dfrac{1}{2}  \times \sqrt{289+4\cdot y}} = \dfrac{17}{2} \pm \sqrt{\dfrac{289}{4} +\dfrac{4\cdot y}{4} }}

And further simplified as follows;

x = \dfrac{17}{2} \pm \sqrt{\dfrac{289}{4} +y }} = \dfrac{17}{2} \pm \sqrt{y + \dfrac{289}{4} }}

Interchanging x and y in the function of the inverse, m⁻¹(x), we have;

m^{-1}(x) = \dfrac{17}{2} \pm \sqrt{x + \dfrac{289}{4} }}

We note that the maximum or minimum point of the function, m(x) = x² - 17·x found by differentiating the function and equating the result to zero, gives;

m'(x) = 2·x - 17 = 0

x = 17/2

Similarly, the second derivative is taken to determine if the given point is a maximum or minimum point as follows;

m''(x) = 2 > 0, therefore, the point is a minimum point on the graph

Therefore, as x increases past the minimum point of 17/2, m⁻¹(x) increases to give;

The \ domain \ restriction \ x \geq \dfrac{17}{2} \ results \ in \ m^{-1}(x) = \dfrac{17}{2} \pm \sqrt{x + \dfrac{289}{4} }} to increase m⁻¹(x) above the minimum.

8 0
2 years ago
If m 2 n, which inequalities must be true? Check all that apply.
anzhelika [568]

Answer:

(a)\ m+ 2.1 > n + 2.1

(b).\ m - (-4) > n - (-4)

(c)\ 9 +m> 6 + n

Step-by-step explanation:

Given

m > n

Required

Select true inequalities

(a)\ m+ 2.1 > n + 2.1

Subtract 2.1 from both sides

m > n

This is true

(b).\ m - (-4) > n - (-4)

Open brackets

m + 4 > n + 4

Subtract 4 from both sides

m > n

(c)\ 9 +m> 6 + n

m> -9+6 + n

m> n-3

This is also true

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just olya [345]
Because each chicken has 2 legs you divide 134 by 2 which is 67 then 24 which basically means he has 36 sheep in total. Hope this helped
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How do I solve this? ​
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