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Vinil7 [7]
3 years ago
5

What is the area in square feet of a 100 yard by 60 yard football field

Mathematics
1 answer:
vitfil [10]3 years ago
6 0

Yards=6000

Feet=18000

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Can someone help me please
nataly862011 [7]

Answer:

D is 90 E is 81 F is 99

Step-by-step explanation:

D is 90 because a straight angle equals 180 degrees. E is 81 because it is directly across from 81. F is 99 because 180-81 is 99

7 0
2 years ago
What is the value of y in the equation 6.4x + 2.8y = 44.4, when x = 3?
Andrej [43]

Answer:

y = 9

Step-by-step explanation:

So if x = 3, we can sub that into the equation.

This gives us:

6.4 (* 3) + 2.8y = 44.4

so:

19.2 + 2.8y = 44.4

25.2 = 2.8y

so

y = 9

5 0
3 years ago
Read 2 more answers
What is the quotient when 4x3 + 2x + 7 is divided by x + 3?
Arte-miy333 [17]

Answer:

The quotient of this division is (4x^2 -12x + 38). The remainder here would be -26.

Step-by-step explanation:

The numerator 4x^3 + 2x + 7 is a polynomial about x with degree 3.

The divisor x + 3 is a polynomial, also about x, but with degree 1.

By the division algorithm, the quotient should be of degree 3 - 1 = 2, while the remainder shall be of degree 1 - 1 = 0 (i.e., the remainder would be a constant.) Let the quotient be a\,x^2 + b\, x + c with coefficients a, b, and c.

4x^3 + 2x + 7 = \left(a\,x^2 + b\, x + c\right)(x + 3).

Start by finding the first coefficient of the quotient.

The degree-three term on the left-hand side is 4 x^3. On the right-hand side, that would be a\, x^3. Hence a = 4.

Now, given that a = 4, rewrite the right-hand side:

\begin{aligned}&\left(4\,x^2 + b\, x + c\right)(x + 3) \cr =& \left(4x^2 + (b\, x + c)\right)(x + 3) \cr =& 4x^2(x + 3) + (bx + c)(x + 3) \cr =& 4x^3 + 12x^2 + (bx + c)(x + 3)\end{aligned}.

Hence:

4x^3 + 2x + 7 = 4x^3 + 12x^2 + (b\,x + c)(x + 3)

Subtract \left(4x^3 + 12x^2\right from both sides of the equation:

-12x^2 + 2x + 7 = (b\,x + c)(x + 3).

The term with a degree of two on the left-hand side has coefficient (-12). Since the only term on the right hand side with degree two would have coefficient b, b = -12.

Again, rewrite the right-hand side:

\begin{aligned}&\left(-12 x + c\right)(x + 3) \cr =& \left(-12 x+ c\right)(x + 3) \cr =& (-12x)(x + 3) + c(x + 3) \cr =& -12x^2 -36x + (bx + c)(x + 3)\end{aligned}.

Subtract -12x^2 -36x from both sides of the equation:

38x + 7 = c(x + 3).

By the same logic, c = 38.

Hence the quotient would be (4x^2 - 12x + 38).

6 0
3 years ago
What is a monomial of the 2nd degree with a leading coefficient of 3
MissTica

Answer:

the answer is a quadratic

Step-by-step explanation:

A second degree polynomial is also called a "quadratic." Examples are 4x2, x2 - 9, or 6x2 + 13x + c. Just for fun, a third degree polynomial is called a "cubic", a fourth degree is called a "quartic", and a fifth degree polynomial is called a "quintic.

7 0
3 years ago
Haya la integral de xarcsenx/((1-x^2)^1/2). Utiliza la sustitución de t= arcsenx
ikadub [295]

Answer:

<em>Explicación más abajo</em>

Step-by-step explanation:

Integración Indefinida

La integral

I=\int \dfrac{x .arcsen\left(x\right)}{\sqrt{1-x^2}}

Se resuelve con el cambio de variables:

t=arcsen(x)

Una vez hechos los cambios, la integral se resuelve en función de t:

I=sen(t)-t.cos(t)+C

Hay que devolver los cambios para mostrarla en función de x.

El cambio de variables también se puede escribir:

x=sen(t)

Recordando que

cos(t)=\sqrt{1-sen^2(t)}

Entonces:

cos(t)=\sqrt{1-x^2}

Devolviendo los cambios:

I=sen(t)-t.cos(t)+C=x-arcsen(x)\sqrt{1-x^2}+C

Es la respuesta correcta

7 0
2 years ago
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