The limitation of computer are:
- No self-intelligence
- No feeling
- No learning power
- Dependency
Answer: provided in the explanation section
Explanation:
Given that:
Assume D(k) =║ true it is [1 : : : k] is valid sequence words or false otherwise
now the sub problem s[1 : : : k] is a valid sequence of words IFF s[1 : : : 1] is a valid sequence of words and s[ 1 + 1 : : : k] is valid word.
So, from here we have that D(k) is given by the following recorance relation:
D(k) = ║ false maximum (d[l]∧DICT(s[1 + 1 : : : k]) otherwise
Algorithm:
Valid sentence (s,k)
D [1 : : : k] ∦ array of boolean variable.
for a ← 1 to m
do ;
d(0) ← false
for b ← 0 to a - j
for b ← 0 to a - j
do;
if D[b] ∧ DICT s([b + 1 : : : a])
d (a) ← True
(b). Algorithm Output
if D[k] = = True
stack = temp stack ∦stack is used to print the strings in order
c = k
while C > 0
stack push (s [w(c)] : : : C] // w(p) is the position in s[1 : : : k] of the valid world at // position c
P = W (p) - 1
output stack
= 0 =
cheers i hope this helps !!!
Answer:
The answer is "Option A".
Explanation:
In the given question the method toString() is used that converts any value into a string. In this code two print method is used, that can be described as follows:
- In the first method, object1 is created, which is used to print all object values.
- In the second method, object1 uses the toString() method, which converts all values into a string, that's why the answer to this question is "True".
The publisher tab in the application control allows you to manage the various certificates that are used to sign to binaries. Publisher allow executables of a particular vendor, signed by a security certificate issued
to the vendor by a Certificate Authority. Also, all applications and binary files either added
to or modified on an endpoint that are signed by the certificate are automatically added to
the whitelist.
The answer is: [A]: "bibliographic generators" .
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