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JulijaS [17]
3 years ago
14

How to solve? I prob know it I'm just stressing and panicking from all other stuff I gotta do

Mathematics
1 answer:
Nata [24]3 years ago
8 0
Left one i think thats the one 
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What is -1/3+w=5 3/8 express in simplest form
Elodia [21]
Let's solve your equation step-by-step.<span><span><span><span>
</span></span></span></span>\frac{-1}{3}<span><span>+w</span>=<span>5</span></span><span>\frac{3}{8}</span>
Step 1: Simplify both sides of the equation.<span><span>
w+</span></span>\frac{-1}{3}<span>=</span><span>\frac{43}{8}</span>
Step 2: Add \frac{1}{3} to both sides.<span><span><span>
w+</span></span></span>\frac{-1}{3}<span><span>+</span></span><span>\frac{1}{3}</span><span>=</span>\frac{43}{8}<span>+</span><span>\frac{1}{3}</span><span>
w=</span><span>\frac{137}{24}</span>


Answer:<span>w=5</span><span>\frac{17}{24}</span>
6 0
4 years ago
Line VW has a slope of 5. What is the slope of a line parallel to VW?
vovangra [49]

Answer:

D.5

Step-by-step explanation:

5 because in order for the line to be parallel the slope needs to be the same

4 0
3 years ago
Round 9,909.937 to 2 decimal places
babymother [125]
9,909.94 that is the answer
3 0
4 years ago
12.com
NemiM [27]
Answer: base times height divided by two
4 0
3 years ago
I’m what quadrant does theta lie if the following statements are true? Sec(theta)&lt;0 and (sec (theta) )(csc (theta) ) &gt; 0
viktelen [127]

Because the cosine and sine must be negative when evaluated in theta, the angle lies on the third quadrant.

<h3>In which quadrant is the endpoint of the segment that defines the angle?</h3>

We know that if:

  • cos(θ) > 0, then we are on the first or fourth quadrant
  • sin(θ) > 0, then we are on first or second quadrant.

Here we know that:

sec(θ) < 0

And we know that:

sec(θ)  = 1/cos(θ)

Then we have cos(θ) < 0

We also have that:

sec(θ)*csc(θ) > 0

Because sec(θ) < 0, we must have that csc(θ) < 0.

Remember: csc(θ) = 1/sen(θ)

Then sen(θ) < 0.

Then we have the two conditions:

sen(θ) < 0

cos(θ) < 0

  • The cosine is negative on the third and second quadrants.
  • The sine is negative on the third and fourth quadrants.

The only quadrant where both are negative is the third quadrant, so that is the correct option.

If you want to learn more about trigonometric functions:

brainly.com/question/8120556

#SPJ1

6 0
2 years ago
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