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Cloud [144]
3 years ago
8

Write the equation of the line that is parallel to the given segment and that passes through the point (-3,0).

Mathematics
1 answer:
grandymaker [24]3 years ago
5 0

Answer:

Option (B)

Step-by-step explanation:

In the figure attached,

A straight line is passing through two points (0, 2) and (3, 1).

Slope of this line (m_1) = \frac{y_2-y_1}{x_2-x_1}

                                   = \frac{2-1}{0-3}

                                   = -\frac{1}{3}

Let the slope of a parallel to the line given in the graph = m_2

By the property of parallel lines,

m_1=m_2

m_2=-\frac{1}{3}

Equation of a line passing through a point (x', y') and slope 'm' is,

y - y' = m(x - x')

Therefore, equation of the parallel line which passes through (-3, 0) and having slope = -\frac{1}{3} will be,

y-0=-\frac{1}{3}(x+3)

y=-\frac{1}{3}x-1

Option (B). will be the answer.

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