Question

What is the remainder when (3x4 + 2x3 – x2 + 2x – 14) ÷ (x + 2) ?

Answer 1

Answer:

Remainder: 10

Step-by-step explanation:

Given: $(3x^4+2x^3-x^2+2x-14)\div (x+2)$

We need to find the remainder of the division polynomial.

Using synthetic division:

-2  |  3        2       -1        2       -14     |

                -6        8      -14       24

       3       -4        7      -12        10

Please see the attachment for steps.

At last we get a number 10.

Therefore, 10 is remainder of division.

Answer 2

We are asked to find out the remainder when  (3x4 + 2x3 – x2 + 2x – 14) is divided by (x + 2). In this case, we just have to substitute the numerator polynomial by the factor which is -2. Therefore,  3*(-2)^4 + 2*(-2)^3 – (-2)^2 + 2*-2 – 14 = 10