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3 years ago

if maruanne father calls and says he needs 13 pounds of potting soil, how many additional bags should she buy?

1 answer:

5 0

2 bags. She needs to buy 2 bags of 10 pounds of potting soil.

20-13=7

2 more bags will give Marunne's father all the soil he needs and 7 pounds left over.

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It takes 0.5 gallon of cream to make 1 pound of butter.

Pavlova-9 [17]

Yes I think it really is the correct answer

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2 years ago

[x^2+2y]^3 expand it

777dan777 [17]

$(a + b) {}^{3} = a {}^{3} + 3a {}^{2} b + 3ab {}^{2} + b {}^{3} \\ \\ x {}^{6} + 6x {}^{4} y + 12x {}^{2} y {}^{2} + 8y {}^{3}$

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3 years ago

Read 2 more answers

I need help finding this answer because I am pretty sure it’s C but I don’t know

malfutka [58]

Answer: A) -9

Step-by-step explanation:

If x = -2

Then $3^{x}$ = $3^{-2}$

So, it is -9

5 0

2 years ago

((60 points to whoever answers all of these))

Readme [11.4K]

1. 9^2

2. 15^3

3. 14^3

4. 11^5

5. 16^4

3 0

3 years ago

Read 2 more answers

Find the roots of:

Elena-2011 [213]

$\large\displaystyle\text{$\begin{gathered}\sf \pmb{1) \ 2x^3-7x^2+8x-3=0 } \end{gathered}$}$

Synthetic division is used since the equation is of the third degree. The divisors of -3 are 1, -1, 3, +3. So:

| 2 -7 8 -3

1 | 2 -5 3

| 2 -5 3 0

1 | 2 -3

2 -3 0

So the factorization is (x-1)² (2x-3)=0. So:

$\bf{ x_1=x_2=1 \qquad x_2=\dfrac{3}{2} }$

$\large\displaystyle\text{$\begin{gathered}\sf \pmb{2) \ x^3-x^2-4=0 } \end{gathered}$}$

Synthetic division is used since the equation is of the third degree. The divisors of -4 are 1, -1, 2, -2, 4, -4. So:

| 1 -1 0 -4

2 | 2 2

1 2 2 0

So the factorization is (x-2)(x²+x+2)=0 . When calculating the discriminant of the trinomial, it is concluded that it has no roots since the result is negative. So you only have one solution.

$\bf{ 1^2-4(2)(2)=1-16=-15 < 0 \quad \Longrightarrow \quad x=2 }$

$\large\displaystyle\text{$\begin{gathered}\sf \pmb{3) \ 6x^3+7x^2-9x+2=0 } \end{gathered}$}$

Synthetic division is used since the equation is of the third degree. The divisors of 2 are 1, -1, 2, -2. So:

| 6 7 9 2

-2 | -12 10 -2

6 -5 1 0

So the factorization is (x+2)(6x²-5x+1)=0 . The quadratic equation is solved by the general formula:

$\bf{ x_{2, 3}&=\dfrac{5\pm \sqrt{(5)^2-4(6)(1)}}{2(6)}=\dfrac{5\pm \sqrt{25-24}}{12}=\dfrac{5\pm 1}{12} }}$

$\large\displaystyle\text{$\begin{gathered}\sf \begin{matrix} x_1=-2&\ \ \ \ \ \ x_{2}=\dfrac{6}{12} \qquad &\ \ \ x_3=\dfrac{4}{12}\\ &\ \ \ x_2=\dfrac{1}{2} \qquad &x_3=\dfrac{1}{3} \end{matrix} \end{gathered}$}$

6 0

2 years ago