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Yuki888 [10]
2 years ago
12

Simplify EXPLAIN your answer.

Mathematics
1 answer:
krek1111 [17]2 years ago
8 0
\frac{x-5}{ x^{3} +27} +  \frac{2}{ x^{2} -9} =  \frac{x-5}{ x^{3}+27 } +  \frac{2}{(x+3)(x-3)}  \\  \\ long-division.. \\  (x^{3} +27)/(x+3) =  x^{2} -3x+9 \\  \\  \frac{x-5}{(x+3)( x^{2} -3x+9)} +  \frac{2}{(x+3)(x-3)}   \\  \\  \frac{x-5}{(x+3)( x^{2} -3x+9)}* \frac{x-3}{x-3}  +  \frac{2}{(x+3)(x-3)} * \frac{x^{2} -3x+9}{ x^{2} -3x+9} =  \frac{(x-5)(x-3)+2( x^{2} -3x+9)}{(x+3)(x-3)( x^{2} -3x+9)}

\frac{(x-5)(x-3)+2( x^{2} -3x+9)}{(x+3)(x-3)( x^{2} -3x+9)} = \frac{ x^{2} -8x+15+2x^{2} -6x+18}{(x+3)(x-3)( x^{2} -3x+9)}  \\  \\ \frac{ 3x^{2} -14x+33}{(x+3)(x-3)( x^{2} -3x+9)}
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3 years ago
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Answer:

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Step-by-step explanation:

Since the two polygons are similar, the sides are proportional to each other.  Using a proportion, you can solve for 'x' using cross-multiplication and division:

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