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Alja [10]
3 years ago
13

Need Help

Mathematics
1 answer:
EastWind [94]3 years ago
4 0
1)\ 21x^3-18x^2y+24xy^2=3x(7x^2-6xy+8y^2)\\\\2)\ a^2+7a-18=a^2+9a-2a-18=a(a+9)-2(a+9)\\=(a+9)(a-2)\\\\3)\ b^2+8b+7=b^2+b+7b+7=b(b+1)+7(b+1)\\=(b+1)(b+7)\\\\4)\ 4f^2-64=4(f^2-16)=4(f^2-4^2)=4(f-4)(f+4)\\\\5)\ 9x^2+25-not\ factorable

6)\ 8j^3k-4jk^3-7-not\ factorable\\\\8)\ 2ak-6a+k-3=2a(k-3)+1(k-3)=(k-3)(2a+1)\\\\9)\ y^2+18y+81=y^2+2y\cdot9+9^2=(y+9)^2=(y+9)(y+9)
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Which set of numbers forms a right triangle?
Tanzania [10]

Answer:

C

Step-by-step explanation:

If you think about it hard enough, and look at it real hard, you can see. Think of like a capital L. 7 tall and 7 wide. I'm not sure but thats what I think.

5 0
3 years ago
Which linear function represent the table?​
rodikova [14]

Answer:

Step-by-step explanation:So, if the graph is a straight line, it is the graph of a linear function. From a table, you can verify a linear function by examining the x and y values. The rate of change for y with respect to x remains constant for a linear function. This rate of change is called the slope.Mar 9, 2011

7 0
3 years ago
Read 2 more answers
10) A rhombus has a<br> diagonal 8.6 mm long<br> and an area of 81.7 mm. what is the<br> perimeter?
BaLLatris [955]

Answer:

P=41.72

Step-by-step explanation:

S=ACxDB/2

81.7=8.6xDB/2

81.7=4.3xDB|:4.3

19(mm)=DB

DO=19/2=9.5

OC=8.6/2=4.3

(O is the center of the rhombus, where two diagonals meet)

a²+b²=c² (DO²+OC²=DC²)

9.5²+4.3²=c²

90.25+18,49=c²

√108,74=√c²

c≈10.43

P=4c

P=4x10.43

P=41.72

Hope it helps:)

6 0
2 years ago
Is there some people who dont wear there retainer and still have straight teeth? cause mine still is
RideAnS [48]

Answer:

I Think Yes!

Step-by-step explanation:

Cause I Also Have A Straight Teeth and Also I Don't Wear Retainer!!

5 0
3 years ago
A group of 5 men are meeting for lunch.
Sladkaya [172]

Tile:

<h2>See the explanation.</h2>

Step-by-step explanation:

(a)

There were total 5 men wearing coats.

5 coats can be returned to 5 men in 5! = 120 ways.

The coats can be returned to the accurate persons only in 1 way.

Hence, the probability that each man gets the correct coat is \frac{1}{120}.

(b)

At the time of returning the first coat, the hostess will have 5 choices and for the second she will have 4 choices.

Hence, in 5\times4 = 20 ways the hostess can return the 2 coats.

There is only 1 possible case that each of the coats will return to the correct owner.

Hence, the required probability is \frac{1}{20}.

6 0
3 years ago
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