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Alja [10]
3 years ago
13

Need Help

Mathematics
1 answer:
EastWind [94]3 years ago
4 0
1)\ 21x^3-18x^2y+24xy^2=3x(7x^2-6xy+8y^2)\\\\2)\ a^2+7a-18=a^2+9a-2a-18=a(a+9)-2(a+9)\\=(a+9)(a-2)\\\\3)\ b^2+8b+7=b^2+b+7b+7=b(b+1)+7(b+1)\\=(b+1)(b+7)\\\\4)\ 4f^2-64=4(f^2-16)=4(f^2-4^2)=4(f-4)(f+4)\\\\5)\ 9x^2+25-not\ factorable

6)\ 8j^3k-4jk^3-7-not\ factorable\\\\8)\ 2ak-6a+k-3=2a(k-3)+1(k-3)=(k-3)(2a+1)\\\\9)\ y^2+18y+81=y^2+2y\cdot9+9^2=(y+9)^2=(y+9)(y+9)
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Please can someone tell me the defenitions of each of these terms?
Xelga [282]
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5 0
3 years ago
1. Find the slope of the line that passes through the points (9, 7) and (2, 9).
Lesechka [4]

Answer:

Step-by-step explanation:

Slope of line passing through (x₁, y₁) and (x₂, y₂) = (y₂-y₁)/(x₂-x₁)

Slope of line passing through (9, 7) and (2, 9) = (9-7)/(2-9) = -2/7

3 0
3 years ago
Read 2 more answers
What is the measure of angle T in this triangle? Enter your answer as a decimal in the box. Round only your final answer to the
Angelina_Jolie [31]

Answer:

28.07

Step-by-step explanation:

test

4 0
3 years ago
In the figure below, the segment is parallel to one side of the triangle. The ratio of 12 to y is 1:2 1:3 1:4 2:3
Brrunno [24]

Answer:

Option B. 1 : 3

Step-by-step explanation:

There are two triangles shown in the picture attached ΔABC and ΔCD.

In these triangles sides AB and DE are parallel and BC is transverse line so ∠ABC = ∠EDC (corresponding angles)

Similarly AC is transverse to parallel lines AB and DE, so ∠BAC = ∠DEC (corresponding angles)

∠ACB is common in both the triangles.

Therefore ΔABC and ΔDEC are similar.

We know in similar triangles corresponding sides are in the same ratio.

\frac{AB}{ED}=\frac{AC}{EC}

\frac{y}{12}=\frac{30+15}{15}=\frac{45}{15}=3:1

Therefore ratio of y and 12 is equal to 3 : 1

Or ratio of 12 to y is 1 : 3

Option B is the answer.

7 0
4 years ago
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You include $\frac{1}{2}$
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