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Alja [10]
3 years ago
13

Need Help

Mathematics
1 answer:
EastWind [94]3 years ago
4 0
1)\ 21x^3-18x^2y+24xy^2=3x(7x^2-6xy+8y^2)\\\\2)\ a^2+7a-18=a^2+9a-2a-18=a(a+9)-2(a+9)\\=(a+9)(a-2)\\\\3)\ b^2+8b+7=b^2+b+7b+7=b(b+1)+7(b+1)\\=(b+1)(b+7)\\\\4)\ 4f^2-64=4(f^2-16)=4(f^2-4^2)=4(f-4)(f+4)\\\\5)\ 9x^2+25-not\ factorable

6)\ 8j^3k-4jk^3-7-not\ factorable\\\\8)\ 2ak-6a+k-3=2a(k-3)+1(k-3)=(k-3)(2a+1)\\\\9)\ y^2+18y+81=y^2+2y\cdot9+9^2=(y+9)^2=(y+9)(y+9)
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grandymaker [24]

Answer:

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Step-by-step explanation:

you can divide the second term by the first term to solve

39/-13 = -3

then,  I like to check that this fits with the third term

39*-3 = -117

so the common ratio is -3

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Step-by-step explanation:

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