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Zina [86]
3 years ago
13

A computer randomly picks a number from the group 75, 76, 77, 78, 79.

Mathematics
2 answers:
Scilla [17]3 years ago
5 0
2/5 or 0.4 Because only two of the five numbers are even or greater than 78
Alex3 years ago
5 0
3/5 because there is one number higher than 78 and (76,and 78) are even number so there are 2 possibilities out of 5 .
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Please help! All the questions.
Yuri [45]
5) 33-25
6) 33-35
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8)’10
5 0
3 years ago
20% of a number is 16. What is 50% of the same number?
trapecia [35]
16 x 5= 80. 80 divided by 2 (50 percent) is 40.
5 0
2 years ago
What is the slope of the line that passes through the points ( − 1 , − 7 ) (−1,−7) and ( 1 , − 13 ) (1,−13)? Write your answer i
Paraphin [41]

Answer:

y = -3x -10

Step-by-step explanation:

Slope-intercept formula: \frac{y_2-y_2}{x_2-x_1}

Find slope of  (−1, −7) and (1, -13)

\frac{y_2-y_2}{x_2-x_1}\\\\\\frac{-13-(-7)}{1-(-1)}\\\\\\frac{-6}{2}\\\\\-3

y = mx + b

y = -3x +b

y = -3x +b\\-7 = -3(-1) + b\\-7 = 3 +b\\-3   -3\\-10 = b

y = -3x -10

Hope this helps!

3 0
2 years ago
Pattern A follows the rule "add 5" and Pattern B follows the rule "subtract 2."
xxTIMURxx [149]

Answer:

(25,12)

Step-by-step explanation:

pattern A=20+5

=25

pattern B=14-2

=12

25,12

4 0
2 years ago
The maximum afternoon temperature in Granderson is modeled by t=60-30 cos (x<img src="https://tex.z-dn.net/?f=%20%5Cpi%20" id="T
kicyunya [14]
The equation is t=60-30 cos (x \frac{\pi}{6})

the -30 expression, is subtracting, if negative, from the 60
if the cosine returned is negative, you'd end up with a +30,
negative * negative = positive

and then the 30 expression will ADD to the 60 amount
so the temperature "t" is highest, when the 30 expression, is
positive and and it's highest

when does that happen, when cosine is negative and at its highest,
well, cosine range is -1\le cos(\theta ) \le 1
so the lowest value cosine can provide is -1, when is cosine -1?
well, at \pi

so...  let's find a value that makes that expression to cos(\pi)

\bf t=60-30 cos (x \frac{\pi}{6}) \qquad x=6&#10;\\\\&#10;thus&#10;\\\\&#10;t=60-30 cos (6 \frac{\pi}{6})\implies t=60-30 cos (\pi )&#10;\\\\&#10;t=60-30[-1]\implies t=60+30\implies t=90

----------------------------------------------------------------------------------------
so...for August, that'll mean


\bf t=60-30 cos (x \frac{\pi}{6}) \qquad x=7&#10;\\\\&#10;t=60-30 cos (\frac{7\pi}{6})\implies t=60-30\left( -\cfrac{\sqrt{3}}{2} \right)&#10;\\\\&#10;t=60+(15\cdot \sqrt{3})\implies t\approx85.98^o


4 0
3 years ago
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