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2 years ago

What is 4/5 equal to?

Mathematics

1 answer:

Anna35 [415]2 years ago

6 0

4/5=0.8

since 4/5 is an inquelvient fraction it gets turned into a decimal

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Sebastian is going to deposit $790 in an account that earns 6.8% interest compounded annually his wife Yolanda will deposit $815

marissa [1.9K]

Answer: sorry dont know what to tell you im struggling too

Step-by-step explanation:

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3 years ago

The distance around our schools playing field is 300 meters. if our coach wants us to run 3 kilometers how many times will we ne

galina1969 [7]

3 kilometers is equal to 3000 meters
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3 years ago

True or false? Rates can be adjusted for different time periods. If you know how many parts can be made in an hour, then you can

julsineya [31]

Answer:

True

Step-by-step explanation:

The whole point of units conversion is to take a value expressed in one set of units (parts per hour) and translate it to a different set of units (parts per week). The rate does not have to involve time.

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3 years ago

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Elenna [48]

9.6958 rounded to the nearest hundredth is 9.70
-
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2 years ago

Consider a tank used in certain hydrodynamic experiments. After one experiment the tank contains liters of a dye solution with a

Alja [10]

Answer:

t = 460.52 min

Step-by-step explanation:

Here is the complete question

Consider a tank used in certain hydrodynamic experiments. After one experiment the tank contains 200 liters of a dye solution with a concentration of 1 g/liter. To prepare for the next experiment, the tank is to be rinsed with fresh water flowing in at a rate of 2 liters/min, the well-stirred solution flowing out at the same rate.Find the time that will elapse before the concentration of dye in the tank reaches 1% of its original value.

Solution

Let Q(t) represent the amount of dye at any time t. Q' represent the net rate of change of amount of dye in the tank. Q' = inflow - outflow.

inflow = 0 (since the incoming water contains no dye)

outflow = concentration × rate of water inflow

Concentration = Quantity/volume = Q/200

outflow = concentration × rate of water inflow = Q/200 g/liter × 2 liters/min = Q/100 g/min.

So, Q' = inflow - outflow = 0 - Q/100

Q' = -Q/100 This is our differential equation. We solve it as follows

Q'/Q = -1/100

∫Q'/Q = ∫-1/100

㏑Q = -t/100 + c

$Q(t) = e^{(-t/100 + c)} = e^{(-t/100)}e^{c} = Ae^{(-t/100)}\\Q(t) = Ae^{(-t/100)}$

when t = 0, Q = 200 L × 1 g/L = 200 g

$Q(0) = 200 = Ae^{(-0/100)} = Ae^{(0)} = A\\A = 200.\\So, Q(t) = 200e^{(-t/100)}$

We are to find t when Q = 1% of its original value. 1% of 200 g = 0.01 × 200 = 2

$2 = 200e^{(-t/100)}\\\frac{2}{200} = e^{(-t/100)}$

㏑0.01 = -t/100

t = -100㏑0.01

t = 460.52 min

6 0

3 years ago