Question

Solve 6y2-5y-6 = 0 using the quadratic formula.

Answer 1

Answer:

$y=\frac{3}{2}$ or $y=-\frac{2}{3}$

Step-by-step explanation:

We have the expression

$6y^2-5y-6 = 0$

For an equation of the form $ay^2 +by +c$  the quadratic formula is

$y=\frac{-b \± \sqrt{b^2 -4ac}}{2a}$

In this case

$a = 6\\b= -5\\c =-6$

$y=\frac{-(-5) \± \sqrt{(-5)^2 -4(6)(-6)}}{2(6)}$

$y_1=\frac{3}{2}$

$y_2=-\frac{2}{3}$

Answer 2

Answer:

Ay=3 over 2 or y=-2 over 3

Step-by-step explanation:

the quadratic formula: y={-b±√(b²-4ac)}/2a

In the equation 6y²-5y-6= 0, a=6, b=-5, c= -6

Substituting for the values in the formula we get:

{-(-5)±√[(-5²)-4(6)(-6)}/2(6)

{5±√169}12

={5±13}/12

(5+13)/12=3/2 or (5-13)/12= -2/3