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Alja [10]
4 years ago
11

10+what can give me 49

Mathematics
2 answers:
nlexa [21]4 years ago
4 0
10+ ?= 49
⇒ ?= 49-10
⇒ ?= 39

10 plus 39 can give you 49~
sineoko [7]4 years ago
3 0
X+y=49
x=10
y=?
x+y=49
10+y=49
y= 49-10=39
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Help pls I’ll give extra points
Svet_ta [14]

Answer:

increases

Step-by-step explanation:

3 0
3 years ago
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Find all points (x, y) where the functions f(x), g(x), h(x) have the same value: f(x) = 2^(x−5) + 3, g(x) = 2x − 5, h(x) = 8/x +
Anna11 [10]

Answer:

The point where all three lines meet is (8, 11)

Step-by-step explanation:

The given functions are;

f(x) = x²⁽ˣ ⁻ ⁵⁾ + 3

g(x) = 2·x - 5

h(x) = 8/x + 10

Equating the simpler functions g(x) to h(x) to find the points of the same value gives;

2·x - 5 = 8/x + 10

2·x - 15 = 8/x

2·x² - 15·x = 8

2·x² - 15·x - 8 = 0

With the aid of an online application, we have;

(2·x + 1)(x - 8) = 0

x = -1/2, or x = 8

The y-values at the point of intersection, is given as follows;

g(x) = 2·x - 5 = 2×(-1/2) - 5 = -6 or g(x) = 2·x - 5 = 2×(8) - 5 = 11

The points where g(x) and h(x) meet are (-1/2, -6) and (8, 11)

To check where the point of intersection of the two functions g(x) ang h(x) meet f(x), we have;

At x = -1/2, f(x) =  2^{(0.5 - 5)} + 3 = 3.0442

At x = -1/2, f(x) =  2⁽⁸⁻⁵⁾ + 3 = 8 + 3 = 11

Therefore, the point where all three lines meet = (8, 11).

4 0
3 years ago
( 3 - 1 ) + ( 1 - 2 i ) = <br> A. 4-3i<br> B. 4+3i<br> C. 4+i
nekit [7.7K]
(3-1i)+(1-2i)=(3+1)+(-1i-2i)=4+(-3i)=4-3i

Answer: A. 4 - 3i

3 0
4 years ago
Factor the following<br> a^2-3a-4
Mademuasel [1]

Answer:

Step-by-step explanation:

a² - 3a - 4

Sum = -3

Product = -4

Factors = -4 , 1

a² - 3a - 4 = a² + a - 4a  - 4*1

               =a(a +1) - 4(a + 1)

                = (a +1)(a - 4)

3 0
3 years ago
Read 2 more answers
Because of a manufacturing error, 3 cans of regular soda were accidentally filled with diet soda and placed into a 24-pack. Supp
kipiarov [429]

Answer:

161/184 or 0.875

Step-by-step explanation:

Total number of cans = 24 cans

Total number of diet soda = 3 cans

Total number of regular soda = 21 cans

We are asked to find the probability that:that at least one contain regular soda if two cans are selected randomly

We have two ways for this happening

a) two of the cans are regular soda

b) one of the cans is regular , while one is diet

Hence,

Probability (that at least one contain regular soda) = Probability(that two of the cans are regular soda) + Probability ( one of the cans is regular , while one is diet)

Probability(that two of the cans are regular soda) = 21/24 × 20/23

= 35/46

Probability ( one of the cans is regular , while one is diet) = 21/24 × 3/23

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Probability (that at least one contain regular soda) = 35/46 + 21/184

We find the Lowest common multiple of the denominators = 184

= 35/46 + 21/184

= (35 × 4) + (21 × 1)/184

= 140 + 21/184

= 161/184

= 0.875

Therefore, the probability that at least one can contains regular soda = 161/184 or 0.875

8 0
4 years ago
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