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4 years ago

30/10 as a mixed number

Mathematics

1 answer:

Allushta [10]4 years ago

7 0

Okay well just divide 30 by 10. 30÷10=3 so it is no fraction it is an integer. The answer is 3

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What expression is equivalnt to x +14 +9x-5

elena55 [62]

10x+9 hope it helps

5 0

3 years ago

The sum of four consecutive terms of an arithmetic progression is 32 and the ratio of product of the first and the last term to

OverLord2011 [107]

The four consecutive terms are 2,6,10,14.

Explanation:

Let the four consecutive terms of an arithmetic progression be (a - 3d), (a - d),(a + d), (a + 3d)

It is given that the sum of four consecutive terms is 32.

Thus, adding all the four consecutive terms, we have,

$\begin{array}{r}{a-3 d+a-d+a+d+a+3 d=32} \\{4 a=32} \\{a=8}\end{array}$

Thus, the value of a is 8.

It is also given that the ratio of the product of first and last term to the product of the two middle terms is 7:15. Thud, we have,

$\frac{(a-3d)(a+3d)}{(a-d)(a+d)} =\frac{7}{15}$

Simplifying the terms, we have,

$\begin{aligned} \frac{a^{2}-9 d^{2}}{a^{2}-d^{2}} &=\frac{7}{15} \\ 15\left(a^{2}-9 d^{2}\right) &=7\left(a^{2}-d^{2}\right) \\ 15 a^{2}-135 d^{2} &=7 a^{2}-7 d^{2} \\ 8 a^{2} &=128 d^{2} \end{aligned}$

Now, substituting a = 8, we have,

$\begin{aligned} 8(64) &=128 d^{2} \\ 512 &=128 d^{2} \\ 4 &=d^{2} \\ 2 &=d \end{aligned}$

Thus, the value of d is 2.

Now, we shall substitute the value of a and d in the terms (a - 3d), (a - d),(a + d), (a + 3d), we get, the four consecutive terms.

Thus, the four consecutive terms are 2,6,10,14.

8 0

3 years ago

-3x - (2y)^2 <br><br> pls help

DENIUS [597]

Answer:

$- 3x - 4y ^{2}$

Step-by-step explanation:

$- 3 - 2 ^{2} y ^{2}$

$- 3x - 4y ^{2}$

8 0

3 years ago

The manager of a grocery store wants to determine the average amount of money spent at his store as it compares to the average d

LuckyWell [14K]

The average money spent would be 74.62

3 0

4 years ago

Our class has 50 students. Assuming that no students are born on leap days (February29), what is the probability that no two stu

madreJ [45]

Answer: a) $\dfrac{799}{31250}$ b) $\dfrac{30451}{31250}$

Step-by-step explanation:

Since we have given that

Number of days in a year = 365

Number of students = 50

Probability that no two students share the same birthday. It means each student has different birthday.

Probability(no two students share the same birthday) $=\dfrac{365-1}{365}\times \dfrac{365-2}{365}........\times \dfrac{365-50}{365}$

Probability(no two students share the same birthday) $=\dfrac{^{365}P_{50}}{365^{50}}$

Probability(no two students share the same birthday) $=\dfrac{799}{31250}\approx 0.025568$

Probability that at least one of the students has the same birthday as another student in the class is given by

$1-P(\text{no student share the same birthday})\\\\=1-\dfrac{799}{31250}\\\\=\dfrac{30451}{31250}=0.974432$

5 0

4 years ago