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3 years ago

A person on earth would weigh a lot more on the sun due to increased ________________. gravity mass atoms energy

2 answers:

4 0

A person on Earth would weigh a lot more on the sun due to increased gravity.

The sun is a massive object as compared to the sun. It is assumed that the gravity must be a lot greater as well. It is the strong gravitational pull of the sun that keeps our planets from drifting off into space. No matter where you are the mass of an object will remain constant, so will the energy and the number of atoms they hold.

The answer is gravity.

lozanna [386]3 years ago

3 0

Answer:

Gravity

Explanation:

The weight of a person is given by :

W = m g

Where

m is the mass of the person

g is acceleration due to gravity.

Weight of the person depend on the value of acceleration due to gravity. The mass of the person remains the same in every location. On the surface of earth it is equal to 9.8 m/s². While on surface of sun it is equal to 274 m/s².

Hence, a person on earth would weigh a lot more on the sun due to increased <em>gravity.</em>

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A freshly prepared sample of radioactive isotope has an activity of 10 mCi. After 4 hours, its activity is 8 mCi. Find: (a) the

Maurinko [17]

Answer:

(a). The decay constant is $1.55\times10^{-5}\ s^{-1}$

The half life is 11.3 hr.

(b). The value of N₀ is $2.38\times10^{11}\ nuclei$

(c). The sample's activity is 1.87 mCi.

Explanation:

Given that,

Activity $R_{0}=10\ mCi$

Time $t_{1}=4\ hours$

Activity R= 8 mCi

(a). We need to calculate the decay constant

Using formula of activity

$R=R_{0}e^{-\lambda t}$

$\lambda=\dfrac{1}{t}ln(\dfrac{R_{0}}{R})$

Put the value into the formula

$\lambda=\dfrac{1}{4\times3600}ln(\dfrac{10}{8})$

$\lambda=0.0000154\ s^{-1}$

$\lambda=1.55\times10^{-5}\ s^{-1}$

We need to calculate the half life

Using formula of half life

$T_{\dfrac{1}{2}}=\dfrac{ln(2)}{\lambda}$

Put the value into the formula

$T_{\dfrac{1}{2}}=\dfrac{ln(2)}{1.55\times10^{-5}}$

$T_{\dfrac{1}{2}}=44.719\times10^{3}\ s$

$T_{\dfrac{1}{2}}=11.3\ hr$

(b). We need to calculate the value of N₀

Using formula of $N_{0}$

$N_{0}=\dfrac{3.70\times10^{6}}{\lambda}$

Put the value into the formula

$N_{0}=\dfrac{3.70\times10^{6}}{1.55\times10^{-5}}$

$N_{0}=2.38\times10^{11}\ nuclei$

(c). We need to calculate the sample's activity

Using formula of activity

$R=R_{0}e^{-\lambda\times t}$

Put the value intyo the formula

$R=10e^{-(1.55\times10^{-5}\times30\times3600)}$

$R=1.87\ mCi$

Hence, (a). The decay constant is $1.55\times10^{-5}\ s^{-1}$

The half life is 11.3 hr.

(b). The value of N₀ is $2.38\times10^{11}\ nuclei$

(c). The sample's activity is 1.87 mCi.

4 0

3 years ago

which law of thermodynamics would be violated if heat were to spontaneously flow between two abject which are in thermal equilib

FromTheMoon [43]

Answer:

The law zero of thermodynamics.

Explanation:

The law zero of thermodynamics, which tells us that heat flows from a body at a higher temperature to another body with lower temperature, when the heat transfer is zero, it is said that the two bodies are in thermal equilibrium, their temperatures are equal

7 0

3 years ago

When two substances are mixed together, a color change is observed. Does this mean that a chemical reaction has definitely occur

Elanso [62]

Nope, color change can also occur during a physical change.

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3 years ago

A hot-air balloon is accelerating upward under the influence of two forces, its weight and the buoyant force. for simplicity, co

Elenna [48]

Let V = the volume of the balloon
Force of gravity = V * ?hot * g downward
Buoyant force = V * ?cool * g upward
Net upward force F = V * ?cool * g - V * ?hot * g

F = V g (?cool - ?hot)

Mass of the balloon m = V ?hot

a = F/m = V g (?cool - ?hot)/(V ?hot)

a = g(?cool/?hot - 1)

a = 9.8(1.29/0.93 - 1)

a = 3.79 m/s^2

<span>Answer is 3.79 m/s^2</span>

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3 years ago

Two types of specialized fingerprint

Akimi4 [234]

Two types of fingerprints are

.1. arches

2. loopes

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4 years ago