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riadik2000 [5.3K]
3 years ago
10

Describe each of the three types of hazardous weather forecast?? Please tell ne the answer

Physics
1 answer:
AnnZ [28]3 years ago
6 0
1) severe local storms (These are short-fused, small scalehazardous weather<span> or hydrologic events produced by thunderstorms, including large hail, damaging winds, tornadoes, and flash floods.) 
</span>
2) <span><span>Winter storms – Weather hazards associated with freezing or frozen precipitation (freezing rain, sleet, snow) or combined effects of winter precipitation and strong winds.
</span><span>
3) Fire weather – Weather conditions leading to an increased risk of wildfires.</span></span>
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Electric field lines show the strength and _____ of an electric field.
Gwar [14]
So we want to know what do electric field lines show except strength of the electric field. Electric field lines are lines that show us the field strength and the DIRECTION of the electric field. If the lines point away from the charge that is producing the lines, the charge is positive, and if the lines point towards the charge that is producing them that charge is negative.
8 0
3 years ago
A sprinter starts from rest and reaches a speed of 15 m/s in 4.25 s. Find his acceleration
kakasveta [241]

Answer:

a=3.53 m/s^2

Explanation:

Vo=0 m/s (because he is not moving at the start)

V1=15 m/s

t= 4.25 s

a = (V1-Vo) / t = 15/4.25 = 3.53 m/s^2

5 0
3 years ago
is it possible to breed a black haired long tailed retriever? If so, what percentage is possible? PLEASE answer the corrects ans
Pachacha [2.7K]

Answer: it can be considered a genetic mutation with a history of a Golden Retriever in their blood but it is very rare. and there our some black retrievers you can buy too. i hope i helped

Explanation:

6 0
2 years ago
Read 2 more answers
Two Physics quick help
Free_Kalibri [48]

Answer:

21.3 V, 1.2 A

Explanation:

1.

These resistors are in series, so the net resistance is:

R = R₁ + R₂ + R₃

R = 20 + 30 + 45

R = 95

So the current is:

V = IR

45 = I (95)

I = 9/19

So the voltage drop across R₃ is:

V = IR

V = (9/19) (45)

V ≈ 21.3 V

2.

First, we need to find the equivalent resistance of R₂ and R₃, which are in parallel:

1/R₂₃ = 1/R₂ + 1/R₃

1/R₂₃ = 1/10 + 1/10

R₂₃ = 5

Now we find the overall resistance by adding the resistors in series:

R = R₁ + R₂₃ + R₄

R = 10 + 5 + 10

R = 25

So the current through R₁ is:

V = IR

30 = I (25)

I = 1.2 A

7 0
3 years ago
In a lab experiment, a student is trying to apply the conservation of momentum. Two identical balls, each with a mass of 1.0 kg,
Studentka2010 [4]

Answer:

Second Trial satisfy principle of conservation of momentum

Explanation:

Given mass of ball A and ball B =\ 1.0\ Kg.

Let mass of ball A and B\ is\ m  

Final velocity of ball A\ is\ v_1

Final velocity of ball B\ is\ v_2

initial velocity of ball A\ is\ u_1

Initial velocity of ball B\ is\ u_2

Momentum after collision =mv_1+mv_2

Momentum before collision = mu_1+mu_2

Conservation of momentum in a closed system states that, moment before collision should be equal to moment after collision.

Now, mu_1+mu_2=mv_1+mv_2

Plugging each trial in this equation we get,

First Trial

mu_1+mu_2=mv_1+mv_2\\1(1)+1(-2)=1(-2)+1(-1)\\1-2=-2-1\\-1=-3

momentum before collision \neq moment after collision

Second Trial

mu_1+mu_2=mv_1+mv_2\\1(.5)+1(-1.5)=1(-.5)+1(-.5)\\.5-1.5=-.5-.5\\-1=-1

moment before collision = moment after collision

Third Trial

mu_1+mu_2=mv_1+mv_2\\1(2)+1(1)=1(1)+1(-2)\\2+1=1-2\\3=-1

momentum before collision \neq moment after collision

Fourth Trial

mu_1+mu_2=mv_1+mv_2\\1(.5)+1(-1)=1(1.5)+1(-1.5)\\.5-1=1.5-1.5\\-.5=0

momentum before collision \neq moment after collision

We can see only Trial- 2 shows the conservation of momentum in a closed system.

4 0
3 years ago
Read 2 more answers
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