Answer:
true
Explanation:
if there is no light it's different from when there is
Answer:
Part a)
acceleration = -0.042 m/s/s
Part b)
initial speed = 14.17 m/s
final speed = 5.77 m/s
Explanation:
Part a)
Let the initial velocity of the motorcycle is

now at the end of 80 s let the speed is

after another 120 s let the speed will be

now we know that



also we know that

also we have


now we can say

also we know



Part b)
now we have



so the starting velocity of the trip is

now speed after t = 200 s is given as



D. be transported from place to place
because it does allow c to happen but not directly as it would have to go through condensation first.
When the water is evaporated in the air it can be moved from place to place by the wind.
Answer:
N = 3.54 * 10²³ atoms
Explanation:
The formula to apply here is the idea gas law;
PV = nRT where ;
P= pressure of the gas= 1.013 * 10⁵ Pa
V= volume of the gas = 4/3 * 3.14 *0.15³= 0.01414 m³
n= amount of a substance = ?
R= ideal gas constant= 8.314
T= temperature= 293 K
Applying the values to the formula;
PV = nRT
1.013 * 10⁵ * 0.01414 = n * 8.314*293
n= 1.013 * 10⁵ * 0.01414 / 8.314*293
n= 0.588 moles
1 mole = 6.022 * 10²⁷ atoms/ mole
0.588 moles = 0.588 * 6.022 * 10²⁷
N = 3.54 * 10²³ atoms