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3 years ago

When an electron is removed from an atom, it becomes ______ ion.

Physics

1 answer:

leva [86]3 years ago

3 0

Answer:

answer would be metalluc ion hope it will help you lil bit

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3m/s for 12 seconds how dar would he walk

Sunny_sXe [5.5K]

I think 36m/12s because 3×12 =36

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3 years ago

Atoms are the smallest portions of an element that retain the original characteristics of the element. True or false

kozerog [31]

Answer:

True

Explanation:

Going even smaller than atoms would get you to subatomic particles such as quarks. From there, it is impossible to distinguish elements. So, yes, atoms are the smallest portions of an element that retains the original characteristic of the element.

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3 years ago

In scientific notation, (6.2 x 10^4) x (3.3 x 10^2 ) equals ____________________.

castortr0y [4]

You will get 20460000 as your answer which is broken down into, 2.046 x 10^7 as your number has to be between 1-10.

5 0

2 years ago

Read 2 more answers

A cylinder with a moving piston expands from an initial volume of 0.250 L against an external pressure of 2.00 atm. The expansio

Step2247 [10]

The final volume of the gas is 144.25 L

Explanation:

For an ideal gas kept at constant pressure, the work done by the gas on the surroundings is given by

$W=p\Delta V = p(V_f - V_i)$

where

p is the pressure of the gas

$V_i$ is the initial volume

$V_f$ is the final volume

For the gas in the cylinder in this problem,

p = 2.00 atm

$V_i = 0.250 L$

And we also know the work done,

W = 288 J

So we can solve the equation for $V_f$ , the final volume:

$V_f = V_i + \frac{W}{p}=0.250 + \frac{288}{2.00}=144.25 L$

Learn more about ideal gases:

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#LearnwithBrainly

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2 years ago

The dimensions of a cylinder are changing, but the height is always equal to the diameter of the base of the cylinder. If the he

VashaNatasha [74]

Answer:

dV/dt = 9 cubic inches per second

Explanation:

Let the height of the cylinder is h

Diameter of cylinder = height of the cylinder = h

Radius of cylinder, r = h/2

dh/dt = 3 inches /s

Volume of cylinder is given by

$V = \pi r^{2}h$

put r = h/2 so,

$V = \pi \frac{h^{3}}{4}$

Differentiate both sides with respect to t.

$\frac{dV}{dt}=\frac{3h^{2}}{4}\times \frac{dh}{dt}$

Substitute the values, h = 2 inches, dh/dt = 3 inches / s

$\frac{dV}{dt}=\frac{3\times 2\times 2}{4}\times 3$

dV/dt = 9 cubic inches per second

Thus, the volume of cylinder increases by the rate of 9 cubic inches per second.

6 0

2 years ago