Answer:
40 more paintings in order to maximize sales making a total of 60 paintings
Step-by-step explanation:
Let x= no.of copies above 20
Total Sales(x) = (number of copies)(price per copy)
Sales (x)= (20 +x)(100 –x)
Open bracket
=1200-20x+100x-x^2
=1200+80x-x^2
Derivative of the sales
80-2x=0
80=2x
Divide both sides by 2
40=x
Because Sales(x)= –2, this is maximal by the second derivative test
The artist should make 40 more paintings in order to maximize sales making a total of 60 paintings.
rs + st = rt Plug in the values
3x + 1 + 2x - 2 = 64 Combine like terms (1 and -2)
3x -1 + 2x = 64 Combine like terms (3x and 2x)
-1 + 5x = 64 Add 1 to both sides
5x = 65 Divide both sides by 5
x = 13
-10 + 20 = 10 is the value
