It’s zero, I think. Because
3 doesn’t round up. It’s stays the same. But since there is nothing in the hundred place. It is 0.
um is the end a 3 and 2 or 32 or 3*2?
![\bf \qquad \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{compounded amount}\\ P= \begin{array}{llll} \textit{original amount}\\ \textit{deposited} \end{array}\to &\$14,800\\ r=rate\to 6\%\to \frac{6}{100}\to &0.06\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{semi-annually, meaning twice} \end{array}\to &2\\ t=years\to &4 \end{cases}](https://tex.z-dn.net/?f=%5Cbf%20%5Cqquad%20%5Ctextit%7BCompound%20Interest%20Earned%20Amount%7D%0A%5C%5C%5C%5C%0AA%3DP%5Cleft%281%2B%5Cfrac%7Br%7D%7Bn%7D%5Cright%29%5E%7Bnt%7D%0A%5Cquad%20%0A%5Cbegin%7Bcases%7D%0AA%3D%5Ctextit%7Bcompounded%20amount%7D%5C%5C%0AP%3D%0A%5Cbegin%7Barray%7D%7Bllll%7D%0A%5Ctextit%7Boriginal%20amount%7D%5C%5C%0A%5Ctextit%7Bdeposited%7D%0A%5Cend%7Barray%7D%5Cto%20%26%5C%2414%2C800%5C%5C%0Ar%3Drate%5Cto%206%5C%25%5Cto%20%5Cfrac%7B6%7D%7B100%7D%5Cto%20%260.06%5C%5C%0An%3D%0A%5Cbegin%7Barray%7D%7Bllll%7D%0A%5Ctextit%7Btimes%20it%20compounds%20per%20year%7D%5C%5C%0A%5Ctextit%7Bsemi-annually%2C%20meaning%20twice%7D%0A%5Cend%7Barray%7D%5Cto%20%262%5C%5C%0A%0At%3Dyears%5Cto%20%264%0A%5Cend%7Bcases%7D%20)
now, that will give you "A", or the compounded amount
what's the interest earned? well, subtract the original amount, the Principal, from A, A - P, and you'd be left with the earned interest
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Answer:
Exponential function
Step-by-step explanation:
The general form an exponential function is given by,
.
Now, if we add another constant to the function as,
then the type of function does not alter.
Now, the function is given to be
is a type of exponential function, where, a = 1, b = 2 and c = 5. (Answer)