Answer:
Step-by-step explanation:
Given that a basketball coach will select the members of a five-player team from among 9 players, including John and Peter.
Out of nine players five are chosen at random.
The team consists of John and Peter.
Hence we can sort 9 players as I group, John and Peter and II group 7 players.
Now the selection is 2 from I group and remaining 3 from II group.
Hence no of ways of selecting a team that includes both John and Peter=
=35
Total no of ways =
=126
=
=
Answer:
86
Step-by-step explanation:
1. a+b=14 ⇒ a= 14-b
2. 10a+b=18+10b+a ⇒ a= 2+b
comparing 1 and 2:
14-b= 2+b ⇒ 2b= 12 ⇒ b= 6
a= 14-b= 8
number = 86
reversed number = 68
Answer:
Step-by-step explanation:
if the number of votes is 25, 12 is not majority
but if the number is 23 then 12 is majority
a²+b² = c² where a and b are legs and c is the hypotenuse
So...
a²+4²=13²
a²+16=169
a²=153
a=√153
answer: approx. 12.37 units
−
4
x
+
7
=
2
Step 1: Subtract 7 from both sides.
−
4
x
+
7
−
7
=
2
−
7
−
4
x
=
−
5
Step 2: Divide both sides by -4.
−
4
x
−
4
=
−
5
−
4
x
=
5
4