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slega [8]
3 years ago
14

Plz answer it’s easy giving brainliest

Mathematics
1 answer:
MariettaO [177]3 years ago
5 0
What is the name of that type of math
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What is the domain of h?
sergeinik [125]

Answer:

C

Step-by-step explanation:

  • The domain is all the x numbers for each point
  • So -5,-4,0,2,4
3 0
2 years ago
a building was decorated with 1240 green bulbs , 1350 red bulbs and 90 yellow bulbs how many bulbs were used in all​
MrRa [10]
Answer: 2,680 bulbs were used in all.

I added all of them up so 1240 + 1350 + 90 which equals 2,680.

If you have any questions let me know, have a great day!
5 0
3 years ago
Please help!!!! I need this ASAP Help
Nutka1998 [239]

Answer:

Step-by-step explanation:

If x is -1, then the point on the parabol is (-1,4)

If x is 0, then the point on the parabol is (0,-2)

If x is 1, then the point on the parabol is (1,-6)

8 0
3 years ago
Find the solution of the differential equation dy/dt = ky, k a constant, that satisfies the given conditions. y(0) = 50, y(5) =
irga5000 [103]

Answer:  The required solution is y=50e^{0.1386t}.

Step-by-step explanation:

We are given to solve the following differential equation :

\dfrac{dy}{dt}=ky~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)

where k is a constant and the equation satisfies the conditions y(0) = 50, y(5) = 100.

From equation (i), we have

\dfrac{dy}{y}=kdt.

Integrating both sides, we get

\int\dfrac{dy}{y}=\int kdt\\\\\Rightarrow \log y=kt+c~~~~~~[\textup{c is a constant of integration}]\\\\\Rightarrow y=e^{kt+c}\\\\\Rightarrow y=ae^{kt}~~~~[\textup{where }a=e^c\textup{ is another constant}]

Also, the conditions are

y(0)=50\\\\\Rightarrow ae^0=50\\\\\Rightarrow a=50

and

y(5)=100\\\\\Rightarrow 50e^{5k}=100\\\\\Rightarrow e^{5k}=2\\\\\Rightarrow 5k=\log_e2\\\\\Rightarrow 5k=0.6931\\\\\Rightarrow k=0.1386.

Thus, the required solution is y=50e^{0.1386t}.

8 0
3 years ago
Read 2 more answers
Dimension of a cuboid is 4 m 3 m ad 5 m how many such cuboid can form a cube....... please and urgent..experts please help
larisa [96]

Step-by-step explanation:

We dimension of the smallest cube to be made from cuboids of sides 3 m , 4 m and 5 m will be the least common multiple of 3 m, 4 m and 5 m i.e. 60 m

12 cuboidal should be stacked along 5 m edge to 60 m, 15 cuboids should be stacked along 4 m edge and 20. cuboids should be stacked along edge to make a cube of 60 m edge, Hence number of cuboids are 12× 15 ×20=3600

hope it helps

4 0
3 years ago
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