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slega [8]
4 years ago
14

Plz answer it’s easy giving brainliest

Mathematics
1 answer:
MariettaO [177]4 years ago
5 0
What is the name of that type of math
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I will give brainliest
Sauron [17]

Answer:

230°

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
(-3)+(-5)<br><br> What are the signs and places
Triss [41]
What do the places mean? I’d say the signs are negative since both values are (-3) and (-5), but i don’t know what you mean by placed - if they were placed in a number line, it would go 3 and 5 values left or down.
3 0
3 years ago
Eva would like to buy a flute with an original price of $969.40. Which coupon should she use $75.00 off or 10% off
Dmitriy789 [7]

Answer:

10% off would be $96.94

So using the Coupon for 10% off would be the best deal.

8 0
3 years ago
I need help on this onee plizzzz
nika2105 [10]
(45+20)/(42+45+20+32)
65/139
<span>46.762589928%</span>
4 0
3 years ago
Read 2 more answers
A box of candy hearts contains 52 hearts, of which 19 are white, 10 are tan, 7 are pink, 3 are purple, 5 are yellow, 2 are orang
laiz [17]

<u>Answer-</u>

a. Probability that  three of the candies are white = 0.29

b. Probability that three are white, 2 are tan, 1 is pink, 1 is yellow, and 2 are green = 0.006

<u>Solution-</u>

There are 19 white candies, out off which we have to choose 3.

The number of ways we can do the same process =

\binom{19}{3} = \frac{19!}{3!16!} = 969

As we have to draw total of 9 candies, after 3 white candies we left with 9-3 = 6, candies. And those 6 candies have to be selected from 52-19 = 33 candies, (as we are drawing candies other than white, so it is subtracted)

And this process can be done in,

\binom{33}{6} = \frac{33!}{6!27!} =1107568

So total number of selection = (969)×(1107568) = 1073233392

Drawing 9 candies out of 52 candies,

\binom{52}{9} = \frac{52!}{9!43!} = 3679075400

∴P(3 white candies) = \frac{1073233392}{3679075400} =0.29



Total number of ways of selecting 3 whites, 2 are tans, 1 is pink, 1 is yellow, and 2 are greens is,

\binom{19}{3} \binom{10}{2} \binom{7}{1} \binom{5}{1} \binom{6}{2}

=(\frac{19!}{3!16!}) (\frac{10!}{2!8!}) (\frac{7!}{1!6}) (\frac{5!}{1!4!}) (\frac{6!}{2!4!})

=(969)(45)(7)(5)(15)=22892625

Total number of selection = 3 whites + 2 are tans + 1 is pink + 1 is yellow + 2 greens = 9 candies out of 52 candies is,

\binom{52}{9}=\frac{52!}{9!43!} =3679075400

∴ P( 3 whites, 2 are tans, 1 is pink, 1 is yellow, 2 greens) =

\frac{22892625}{3679075400} = 0.006


6 0
4 years ago
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