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3 years ago

The range is a set of order pairs

Mathematics

1 answer:

spayn [35]3 years ago

7 0

Range usually deals with the y-values , so I really wouldn't consider it a set of ordered pairs

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Find the gradient of the line Joining the points p(-2,6) and Q(3,-2)

Rudiy27

Answer:

$- \frac{8}{5}$

Step-by-step explanation:

$\boxed{gradient = \frac{y1 - y2}{x1 - x2} }$

(x₁, y₁) is the 1st coordinate while (x₂, y₂) is the 2nd coordinate.

Gradient of the line

$= \frac{6 - ( - 2)}{ - 2 - 3}$

$= \frac{6 + 2}{ - 5}$

$= - \frac{8}{5}$

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3 years ago

Name the property:

Neporo4naja [7]

Answer:

B. Commutative Property of Multiplication

Step-by-step explanation:

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2 years ago

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What is 2(-9x-4y-7) simplified

Setler79 [48]

-18x-8y-14 because you need to distribute the digits

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3 years ago

Find the sum of the geometric series 512+256+ . . .+4

mario62 [17]

$\bf 512~~,~~\stackrel{512\cdot \frac{1}{2}}{256}~~,~~...4$

so, as you can see above, the common ratio r = 1/2, now, what term is +4 anyway?

$\bf n^{th}\textit{ term of a geometric sequence}\\\\a_n=a_1\cdot r^{n-1}\qquad \begin{cases}n=n^{th}\ term\\a_1=\textit{first term's value}\\r=\textit{common ratio}\\----------\\r=\frac{1}{2}\\a_1=512\\a_n=+4\end{cases}$

$\bf 4=512\left( \cfrac{1}{2} \right)^{n-1}\implies \cfrac{4}{512}=\left( \cfrac{1}{2} \right)^{n-1}\\\\\\\cfrac{1}{128}=\left( \cfrac{1}{2} \right)^{n-1}\implies \cfrac{1}{2^7}=\left( \cfrac{1}{2} \right)^{n-1}\implies 2^{-7}=\left( 2^{-1}\right)^{n-1}\\\\\\(2^{-1})^7=(2^{-1})^{n-1}\implies 7=n-1\implies \boxed{8=n}$

so is the 8th term, then, let's find the Sum of the first 8 terms.

$\bf \qquad \qquad \textit{sum of a finite geometric sequence}\\\\S_n=\sum\limits_{i=1}^{n}\ a_1\cdot r^{i-1}\implies S_n=a_1\left( \cfrac{1-r^n}{1-r} \right)\quad \begin{cases}n=n^{th}\ term\\a_1=\textit{first term's value}\\r=\textit{common ratio}\\----------\\r=\frac{1}{2}\\a_1=512\\n=8\end{cases}$

$\bf S_8=512\left[ \cfrac{1-\left( \frac{1}{2} \right)^8}{1-\frac{1}{2}} \right]\implies S_8=512\left(\cfrac{1-\frac{1}{256}}{\frac{1}{2}} \right)\implies S_8=512\left(\cfrac{\frac{255}{256}}{\frac{1}{2}} \right)\\\\\\S_8=512\cdot \cfrac{255}{128}\implies S_8=1020$

7 0

3 years ago

Giving out extra points please help

andreyandreev [35.5K]

Answer:

i dont want extra one i only want the though one

5 0

2 years ago