Answer:
thus the probability that a part was received from supplier Z , given that is defective is 5/6 (83.33%)
Step-by-step explanation:
denoting A= a piece is defective , Bi = a piece is defective from the i-th supplier and Ci= choosing a piece from the the i-th supplier
then
P(A)= ∑ P(Bi)*P(C) with i from 1 to 3
P(A)= ∑ 5/100 * 24/100 + 10/100 * 36/100 + 6/100 * 40/100 = 9/125
from the theorem of Bayes
P(Cz/A)= P(Cz∩A)/P(A)
where
P(Cz/A) = probability of choosing a piece from Z , given that a defective part was obtained
P(Cz∩A)= probability of choosing a piece from Z that is defective = P(Bz) = 6/100
therefore
P(Cz/A)= P(Cz∩A)/P(A) = P(Bz)/P(A)= 6/100/(9/125) = 5/6 (83.33%)
thus the probability that a part was received from supplier Z , given that is defective is 5/6 (83.33%)
Answer:
smaller: 3
larger: 27
Step-by-step explanation:
Hope this helps!
I think this question is for you to answer it with your own opinion, think about it and just answer it with what you think :)
Answer:
Statements: Reasons:
1) ∠2 and ∠4 are vertical angles given
2) limes <em>m </em>and <em>n </em>intersect at <em>P </em>definition of vertical angles
3) ∠3 and ∠4 are linear pair definition of linear pair
4) ∠2 and ∠3 are linear pair definition of linear pair
5) m∠3 + m∠4 =180 angle addition postulate
6) m∠2 + m∠3 =180 angle addition postulate
7) m∠2 + m∠3 = m∠3 + m∠4 substitution property
8) m∠2 = m∠4 subtraction property
9) ∠2 ≅ ∠4 definition of congruent(≅) angles
