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MrRa [10]
3 years ago
6

What is three million, seven hundred twenty four in number form

Mathematics
2 answers:
miv72 [106K]3 years ago
8 0

3,000,724 Hope this was what you're looking for!

iris [78.8K]3 years ago
5 0

The answer would be 3,000,724.

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Area for a kite<br> I don’t know how to find the area pls help
dusya [7]

Answer:

63.966

Step-by-step explanation:

Area of a kite is

\frac{pq}{2}

where p and q are the diagonals.

The horinzontial diagonal is 8.

We need to find the vertical diagonal length.

The top triangle diagonal measure is

{4}^{2}  +  {x}^{2}  =  {7}^{2}

16 +  {x}^{2}  = 49

{x}^{2}  = 33

x =  \sqrt{33}

The bottom triangle diagonal measure is

{4}^{2}  +  {x}^{2}  =  {11}^{2}

1 6 +  {x}^{2}  = 121

{x}^{2}  = 105

x =  \sqrt{105}

Add the two diagonals.

\sqrt{105}  +  \sqrt{33}

Substitute this in for the formula

\frac{8 \times ( \sqrt{105}  + \sqrt{33}  }{2}

Which simplified gu

Ives us

63.966

Round if neededd.

7 0
3 years ago
What is the value of a in the equation −14a−5=−12?
-BARSIC- [3]
-14a-5=-12
+5 +5
-14a=-7
Divide -7 by -14a
a=2
7 0
3 years ago
Need help ASAP ITS DUE SOON PLEASE AND SHOW WORK !!!
kumpel [21]

Answer:

33.51032

Step-by-step explanation:

Because equation is 3/4 times r to the 3 power times pi

2 to the 3 power=8

8 times 3/4=32/3

32/3 times pi = 33.51032

3 0
3 years ago
Read 2 more answers
Someone good with trigonometry please help
serg [7]
Tan(52°) = opposite/adjacent = x/35  ⇒ 

x = 35 * tan(52°) = 35 * 1.2799 ≈ 44.80
3 0
3 years ago
A particular brand of tires claims that its deluxe tire averages at least 50,000 miles before it needs to be replaced. From past
Vadim26 [7]

Answer:

We conclude that deluxe tire averages less than 50,000 miles before it needs to be replaced which means that the claim is not supported.

Step-by-step explanation:

We are given that a particular brand of tires claims that its deluxe tire averages at least 50,000 miles before it needs to be replaced. From past studies of this tire, the standard deviation is known to be 8000.

From the 28 tires surveyed, the mean lifespan was 46,500 miles with a standard deviation of 9800 miles.

<u><em>Let </em></u>\mu<u><em> = average miles for deluxe tires</em></u>

So, Null Hypothesis, H_0 : \mu \geq 50,000 miles   {means that deluxe tire averages at least 50,000 miles before it needs to be replaced}

Alternate Hypothesis, H_A : \mu < 50,000 miles    {means that deluxe tire averages less than 50,000 miles before it needs to be replaced}

The test statistics that will be used here is <u>One-sample z test statistics</u> as we know about population standard deviation;

                                  T.S.  = \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = sample mean lifespan = 46,500 miles

            \sigma = population standard deviation = 8000 miles

            n = sample of tires = 28

So, <u><em>test statistics</em></u>  =  \frac{46,500-50,000}{\frac{8000}{\sqrt{28} } }

                               =  -2.315

The value of the test statistics is -2.315.

Now at 5% significance level, the z table gives critical value of -1.6449 for left-tailed test. Since our test statistics is less than the critical value of z as -2.315 < -1.6449, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that deluxe tire averages less than 50,000 miles before it needs to be replaced which means that the claim is not supported.

4 0
3 years ago
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