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MrRa [10]
3 years ago
6

What is three million, seven hundred twenty four in number form

Mathematics
2 answers:
miv72 [106K]3 years ago
8 0

3,000,724 Hope this was what you're looking for!

iris [78.8K]3 years ago
5 0

The answer would be 3,000,724.

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A train is traveling at 60 mph. If the rate of speed increases 4 mph each hour,
Alenkasestr [34]

Answer:

B) 5 hours

Step-by-step explanation:

First, find the amount of mph between 60 and 80:

80 - 60

= 20 mph

Since the speed increases 4 mph per hour, we can find how long it will take to get to 80 mph by dividing 20 by 4:

20/4

= 5

So, the correct answer is B, 5 hours

6 0
3 years ago
Whole number between 1 and 10, and then write its reciprocal.
Natasha_Volkova [10]

Answer:

2

reciprocal: 1/2

brainliest accepted!!!;)

3 0
3 years ago
Need to be done asap!!! I will give u brainliest if ur right
alisha [4.7K]
The answer is the first one, A
3 0
3 years ago
A bookstore has 7 shelves of books about animals. There are 30 books on each shelf. How many books about animals does the bookst
Alenkinab [10]
The answer is 210 .. .

7 0
3 years ago
Solve the 3 × 3 system shown below. Enter the values of x, y, and z. X + 2y – z = –3 (1) 2x – y + z = 5 (2) x – y + z = 4 (3)
Svet_ta [14]
<h2>Answer:</h2>

\boxed{x=1, \y=-1, \ z=2}

<h2>Step-by-step explanation:</h2>

We will use the Gaussian elimination method to solve this problem. To do so, let's follow the following steps:

Step 1: Let's multiply first equation by −2. Next, add the result to the second equation. So:

\begin{array}{ cccc }~~ x&+~~2~ y&-~~~~~ z&~=~-3\\&-~~~5~ y&+~~3~ z&~=~11\\~~ x&-~~~~~ y&+~~~~ z&~=~4\end{array}

Step 2: Let's multiply first equation by −1. Next, add the result to the third equation. Thus:

\begin{array}{ cccc }~~ x&+~~2~ y&-~~~~~ z&~=~-3\\&-~~~5~ y&+~~3~ z&~=~11\\&-~~~3~ y&+~~2~ z&~=~7\end{array}

Step 3: Let's multiply second equation by −35, Next, add the result to the third equation. Therefore:

\begin{array}{ cccc }~~ x&+~~2~ y&-~~~~~ z&~=~-3\\&-~~~5~ y&+~~3~ z&~=~11\\&&+~~\frac{ 1 }{ 5 }~ z&~=~\frac{ 2 }{ 5 }\end{array}

Step 4: solve for z, then for y, then for x:

\frac{ 1 }{ 5 } ~ z & = \frac{ 2 }{ 5 } \\ \\ \boxed{z & = 2}

-5y+3z &= 11\\-5y+3\cdot 2 &= 11\\ \\ \boxed{y &= -1}

By substituting y=-1 \ and \ z=2 into the first equation, we get the x. So:

x+2(-1)-2=-3 \\ \\ x-2-2=-3 \\ \\ \boxed{x=1}

6 0
4 years ago
Read 2 more answers
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