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viktelen [127]
3 years ago
13

Which represents “if x=4, then y=-2”

Mathematics
2 answers:
11111nata11111 [884]3 years ago
6 0
Representa una ecuacion de segundo grado. :v
IRISSAK [1]3 years ago
4 0
You haven't shared the answer choices.

Still, we could invent a function for which the above statement is true:

y = mx + b, and "if x = 4, y = -2" becomes -2 = m(4) + b.  Unfortunately, we have 2 unknowns here.  

If we arbirtrarily let b = 3, then y = mx + b becomes y = mx + 3.  Subst. 4 for x and -2 for y, we get      -2 = m(4) + 3, or -5 = 4m, or m = -5/4.

Then y = mx + b   becomes    y = (-5/4)x + 3.  (this is just an example!!!)


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Help asap please!! <3
IRISSAK [1]

Answer:

False, True, True, False, False

8 0
3 years ago
Read 2 more answers
14. The number of customers that a small
monitta

Answer:

625

Step-by-step explanation:

ok so, 25% of 400 is 100 since 25 is 1/4 of 100 just like 100/400. Now, we do 100+ 400 for the second week which is 500. Now, 500 divided by 25 is next and if we had 4 boxes wed be able to fit 100 in each and the last 100 is split so 100 divided by 4 is 25. so we add 25 to each box. Now we have 125 in each box. so thats it divided by 25% or 1/4. 125 + 500 is 625 and thats your awnser. Have a good day!

3 0
2 years ago
I need help but lol who else hates school
In-s [12.5K]
Also, I hate school, but I do love simple math lol

3 0
3 years ago
What is the definition of infinite solutions?
Maurinko [17]

Answer: A is the correct answer I am 100% positive

Step-by-step explanation:

5 0
3 years ago
Suppose that a poll finds that 31.9​% of taxpayers who filed their tax return electronically​ self-prepared their taxes. If thre
Aneli [31]

Answer: 0.0325

Step-by-step explanation:

Binomial probability distribution formula for x successes in n trials:-

P(X=x)=^nC_x\ p^x\ (1-p)^{n-x}, where n is the number of trials , p is the probability of success.

Given : The probability that taxpayers who filed their tax return are electronically​ self-prepared their taxes : p= 0.319

If three tax returns submitted electronically are randomly​ selected, then the probability that all three were​ self-prepared is given by :-

P(X=3)=^3C_3\ (0.319)^3\ (1-0.319)^{3-3}\\\\=(1) (0.319)^3(1)\\=0.032461759\approx0.0325

Hence, the probability that all three were​ self-prepared =0.0325

6 0
3 years ago
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