2 days late, but the answer is no solution. solving a system of equations means finding where they intersect, but by looking at these equations, you know that they never intersect--they're parallel.
they share a slope (2), making them either parallel or "the same line", but the different x-intercepts (9 and -9) mean that they're different lines. they have no solution, or no intersection point, because they're parallel lines.
Answer:
a = 102.05
b = 393.76
B = 93°
Step-by-step explanation:
The law of sines tells you ...
a/sin(A) = b/sin(B) = c/sin(C)
Since the sum of angles in a triangle is 180°, angle B must be ...
B = 180° -72° -15° = 93°
and the unknown sides must be ...
a = c/sin(C)·sin(A) = 375·sin(15°)/sin(72°) ≈ 102.05192
B = 93°
b = 375·sin(93°)/sin(72°) ≈ 393.75796
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The rounding requirement got cut out of your picture, so we can't help you with that.
Answer:
x<6 this is the answer because the circle is hallow (not including) and going left (less than)
In circle O, RT and SU are diameters. mArc R V = mArc V U = 64°. Thus, option C is correct.
Given that:
mArc R V = mArc V U,
Angle S O R = 13 x degrees
Angle T O U = 15 x - 8 degrees
<h3>How to calculate the angle TOU ?</h3>
∠SOR = ∠TOU (Vertically opposite angles are equal).
Therefore:
13 x = 15x - 8
Subtracting 13x from both sides
13x - 13x = 15x - 8 - 13x
0 = 15x - 13x - 8
2x - 8 = 0
Adding 8 to both sides:
2x - 8 + 8 = 0 + 8
2x = 8
2x/2 = 8/2
x = 4
∠SOR = 13x
= 13(4)
= 52°
∠TOU = 15x - 8
= 15(4) - 8
= 60 - 8
= 52°
Let a = mArc R V = mArc V U
Therefore:
mArc R V + mArc V U + ∠TOU = 180 (sum of angles on a straight line)
Substituting:
a + a + 52 = 180
2a = 180-52
2a = 128
a = 128/2
a= 64°
mArc R V = mArc V U = 64°
In circle O, RT and SU are diameters. mArc R V = mArc V U = 64°. Thus, option C is correct.
Learn more about angles here:
brainly.com/question/2882938
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