4 years ago

Whdss the solutions to the graphs?

Mathematics

1 answer:

Ulleksa [173]4 years ago

4 0

Answer:

where is the picture

i cant see any attachment

Step-by-step explanation:

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If angle 0 is in quadrant I, what is the value of

Brilliant_brown [7]

Answer:

$the \: answer \: is \: c \: = - \frac{ \sqrt{14} }{5}$

Step-by-step explanation:

$\sin^{2}0 + ( \frac{ \sqrt{11} }{5} ) ^{2} = 1( \sin^{2}0 + \cos^{2} 0 = 1)$

${ \sin }^{2}0 + \frac{11}{25} = 1 \\ { \sin }^{2}0 = \frac{14}{25}$

$\sin0_{1} = - \frac{ \sqrt{14}}{5} while \sin0_{2} = \frac{ \sqrt{14} }{5}$

Therfore theta is QI
Therfore sin theta >0
$therefore \: \sin0 = \frac{ \sqrt{14} }{5}$

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2 years ago

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KonstantinChe [14]

Answer:

-2

Step-by-step explanation:

-9=4n-1

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3 years ago

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marishachu [46]

Answer:

$\frac{6n - 4}{8n - 4} = \frac{2}{3}$

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3 years ago

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Nutka1998 [239]

Let i = sqrt(-1) which is the conventional notation to set up an imaginary number

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sqrt(-8) = sqrt(-1*4*2)

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sqrt(-8) = i*2*sqrt(2)

sqrt(-8) = 2i*sqrt(2)

<h3>Answer is choice A</h3>

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