We are given with two solutions: y = x2 + 12x + 30 and 8x – y = 10 and is asked to determinte the solutions of the system of equations. We get y in the second eqn which is equal to 8x -10. we substitute this to first eqn resulting to
8x-10 = x^2 + 12 x + 30. this is a second order equation. x is equal to -2 + 6i and -2 - 6i.
<h3>
Answer: y = -x-2</h3>
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Explanation:
First we need the slope

Then we can find the y intercept using the coordinates of (x,y) = (-4,2)
y = mx+b
2 = -1(-4)+b
2 = 4+b
2-4 = b
-2 = b
b = -2
Alternatively, you can use the other point (x,y) = (3,-5) and m = -1.
Because m = -1 and b = -2, we go from y = mx+b to y = -1x+(-2) which simplifies to y = -x-2
Answer:
(6, - 3 )
Step-by-step explanation:
Given the 2 equations
2x + 5y = - 3 → (1)
2x + 2y = 6 → (2)
Subtracting (1) from (2) term by term will eliminate the x- term
(2x - 2x) + (2y - 5y) = 6 - (- 3), that is
- 3y = 9 ( divide both sides by - 3 )
y = - 3
Substitute y = - 3 in either of the 2 equations and solve for x
Substituting y = - 3 in (1)
2x + 5(- 3) = - 3
2x - 15 = - 3 ( add 15 to both sides )
2x = 12 ( divide both sides by 2 )
x = 6
Solution is (6, - 3 )
Answer:
Equation of the straight line in point-slope form
y -(-7) =
(x-8)
Equation of the straight line
3x +4y +4=0
Step-by-step explanation:
<u><em>Explanation:-</em></u>
Given that the point ( 8,-7) and 
Equation of the straight line passing through the point (x₁, y₁) and having slope 'm'
y - y₁ = m (x-x₁)
y -(-7) =
(x-8)
4( y+7) = -3(x-8)
4y +28 = -3x +24
3x +4y +28 -24 =0
3x +4y +4=0
Answer:
see attached image
Step-by-step explanation: