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viva [34]
3 years ago
13

Zeus Industries bought a computer for $2857. It is expected to depreciate at a rate of 24% per year. What will the value of the

computer be in 3 years?
Round to the nearest penny. Do not type the "$" sign in your answer


******PLEASE HELP******
Mathematics
1 answer:
alexandr1967 [171]3 years ago
6 0
This is an exponential growth/decay problem, and it doesn't really matter which when it comes to the equation because they are both pretty much the same. The formula is A = Pe^(rt), where A is what you end up with, P is the principle value of the object, e is euler's number, r is the rate of decay or growth, and t is the time in years. Since we are looking at depreciation or decay, our r value will be negative. A is what we are solving for (the ending value), P is 2857, r is -.24 and t is 3. So our formula, set up properly, looks like this: A = 2857e^(-.24*3). The first thing to do is to simplify the exponents by multiplying them: A = 2857e^(-.72). Now we're ready to solve! On your calculator, you have a 2nd button and a LN button, when you hit 2nd-->LN you'll get e^(  .  Enter in the -.72 and then hit enter.  You should get .4867522. Now multiply that by 2857 and you'll get 1390.65.  That's what the computer will be worth in 3 years if it depreciates at that rate.
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Write an equation for the line in point-slope and slope-intercept forms.
kobusy [5.1K]

point-slope form: y-y₁ = m(x-x₁)

=============

\rightarrow \sf y - 5 = \dfrac{5}{3} (x-3)

slope-intercept form: y = mx + b

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\rightarrow \sf y - 5 =  \dfrac{5}{3}(x)+ \dfrac{5}{3}(-3)

\rightarrow \sf y - 5 =  \dfrac{5}{3}(x)-5

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\rightarrow \sf y  =  \dfrac{5}{3}(x)

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timama [110]
P=2(L+W)  and P=34 so

2(L+W)=34

L+W=17 so we can say

L=17-W

A=LW using L from above

A=(17-W)W

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30=17W-W^2

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