Answer:
a) 99.97%
b) 65%
Step-by-step explanation:
• 68% of data falls within 1 standard deviation from the mean - that means between μ - σ and μ + σ.
• 95% of data falls within 2 standard deviations from the mean - between μ – 2σ and μ + 2σ.
• 99.7% of data falls within 3 standard deviations from the mean - between μ - 3σ and μ + 3σ.
Mean of 98.35°F and a standard deviation of 0.64°F.
a. What is the approximate percentage of healthy adults with body temperatures within 3 standard deviations of the mean, or between 96.43°F and 100.27°F?
μ - 3σ
98.35 - 3(0.64)
= 96.43°F
μ + 3σ.
98.35 + 3(0.64)
= 100.27°F
The approximate percentage of healthy adults with body temperatures is 99.97%
b. What is the approximate percentage of healthy adults with body temperatures between 97 .71°F and 98.99°F?
within 1 standard deviation from the mean - that means between μ - σ and μ + σ.
μ - σ
98.35 - (0.64)
= 97.71°F
μ + σ.
98.35 + (0.64)
= 98.99°F
Therefore, the approximate percentage of healthy adults with body temperatures between 97.71°F and 98.99°F is 65%
Answer:
1. 3*8*10=240
2.6*6*12=432
Step-by-step explanation:
Hope that helps
Use l*w*h
Sorry, maybe is too late for you, But the answer is:
For example: 4 x 4=16cm² if <span> one pair of opposite sides was made 50% longer and the other pair of opposite sides was made 50% shorter
It became: 6 x 2=12cm</span>²
12/16=0.75
So, the 75% <span>of the square’s area is the area of the new rectangle.</span>
✧･ﾟ: *✧･ﾟ:* *:･ﾟ✧*:･ﾟ✧
Hello!
✧･ﾟ: *✧･ﾟ:* *:･ﾟ✧*:･ﾟ✧
❖ Mean = 4.8 Median = 4.5
The mean is the average. To find the mean add up all the numbers and divide by the number of numbers:
3 + 3 + 4 + 5 + 5 + 9 = 29
29 ÷ 6 = 4.8
To find the mean, keep crossing out numbers until you are left with one number (for an odd amount of numbers). When you have an even amount of numbers, keep crossing out until you are left with 2 numbers. Add those 2 numbers and then divide:
4 + 5 = 9
9 ÷ 2 = 4.5
~ ʜᴏᴘᴇ ᴛʜɪꜱ ʜᴇʟᴘꜱ! :) ♡
~ ᴄʟᴏᴜᴛᴀɴꜱᴡᴇʀꜱ
It is either top left or bottom right, I cannot see the numbers clearly.
