3 years ago

This a 2 part question. F(x) is the graph shown.

1 answer:

5 0

Suppose f(x) is an even function. The range of g(x) = -3f(2x) is [-9, 3].

Suppose f(x) is an odd function. What is the range of 0.5f(x-3) is [-1.5, 0.5]

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15 Points!

Xelga [282]

$f(x)=\dfrac{x-5}{x^2-1}\\\\\text{the horizontal asymptotes}\\\\x^2-1=0\to x^2=1\to x=\pm\sqrt1\to x=-1\ \wedge\ x=1\\\\\text{the vertical asymptotes}\\\\y=\lim\limits_{x\to\pm\infty}\dfrac{x-5}{x^2-1}=\lim\limits_{x\to\pm\infty}\dfrac{\frac{x}{x^2}+\frac{5}{x^2}}{\frac{x^2}{x^2}-\frac{1}{x^2}}=\dfrac{0+0}{1-0}=0$

Answer: B) x = 1, x = -1, y = 0

8 0

3 years ago

Use the Change of Base Formula to evaluate log5 92. Then convert log5 92 to a logarithm in base 3. Round to the nearest thousand

ANTONII [103]

I was thinking that the answer could be

2.810; log3 21.903

OR

 2.810; log3 55.2 

So, log5 of 92 is between 2.5 and 3 Correct answer is A

6 0

3 years ago

Read 2 more answers

Simplify the following expression: 4(x+10)-3x-2-x

Ilia_Sergeevich [38]

4x+40-3x-2-x
(4x-3x-x)=4x-4x=0
(40-2)=38
The answer will be 38

6 0