Answer:
The Answer is: y = -2/3x + 10/3
Step-by-step explanation:
Given points (-1, 4) and (8, -2) first find the slope:
m = (y - y1)/(x - x1)
m = (4 - (-2)) / (-1 - 8)
m = 4 + 2 / -9
m = -6/9 = -2/3
Use the point slope form and point (8, -2) and slove for y:
y - y1 = m(x - x1)
y - (-2) = -2/3(x - 8)
y + 2 = -2/3x + 16/3
y = -2/3x + 16/3 - 2
y = -2/3x + 16/3 - 6/3
y = -2/3x + 10/3
Proof using the point (-1, 4):
f(-1) = -2/3(-1) + 10/3
= 2/3 + 10/3
= 12/3 = 4, giving point (-1, 4)
Hope this helps! Have an Awesome Day!! :-)
Answer:
It’s prime
Step-by-step explanation:
Numbers between 2 and 31 are since these only have 1 and itself.
Answer:
D
Step-by-step explanation:
our basic Pythagorean identity is cos²(x) + sin²(x) = 1
we can derive the 2 other using the listed above.
1. (cos²(x) + sin²(x))/cos²(x) = 1/cos²(x)
1 + tan²(x) = sec²(x)
2.(cos²(x) + sin²(x))/sin²(x) = 1/sin²(x)
cot²(x) + 1 = csc²(x)
A. sin^2 theta -1= cos^2 theta
this is false
cos²(x) + sin²(x) = 1
isolating cos²(x)
cos²(x) = 1-sin²(x), not equal to sin²(x)-1
B. Sec^2 theta-tan^2 theta= -1
1 + tan²(x) = sec²(x)
sec²(x)-tan(x) = 1, not -1
false
C. -cos^2 theta-1= sin^2
cos²(x) + sin²(x) = 1
sin²(x) = 1-cos²(x), our 1 is positive not negative, so false
D. Cot^2 theta - csc^2 theta=-1
cot²(x) + 1 = csc²(x)
isolating 1
1 = csc²(x) - cot²(x)
multiplying both sides by -1
-1 = cot²(x) - csc²(x)
TRUE
