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julsineya [31]
2 years ago
15

If the order of a reaction with the regard to reagent A is 2, when the concentration of A doubles, the rate will

Chemistry
1 answer:
Anarel [89]2 years ago
3 0

Answer:

Rate will double

Explanation:

Since the concentration of A is doubling the rate of reaction will also double, since in this scenario concentration is proportional to rate of reaction. So if the concentration of A were to triple the rate of reaction would also triple.

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Sugar cannot be separated from sugar solution by filtering explain why?​
alexdok [17]

Answer:

The sugar particles are so small that they have dissolved in the water, and can easily pass through the filter.

5 0
2 years ago
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2.0 L of Carbon dioxide is heated from -25.0 °C to Standard Temperature.
RideAnS [48]

The final volume of the gas that was heated from -25.0 °C to standard temperature is 2.2L.

<h3>How to calculate volume?</h3>

The volume of a given gas can be calculated using the Charles law equation as follows:

V1/T1 = V2/T2

Where;

  • V1 = initial volume
  • V2 = final volume
  • T1 = initial temperature
  • T2 = final temperature

  • V1 = 2L
  • V2 = ?
  • T1 = -25°C + 273 = 248K
  • T2 = 273K

2/248 = V2/273

273 × 2 = 248V2

546 = 248V2

V2 = 546/248

V2 = 2.2L

Therefore, the final volume of the gas that was heated from -25.0 °C to standard temperature is 2.2L

Learn more about volume at: brainly.com/question/11464844

5 0
2 years ago
3 waves are shown with a line through their center. The bottom of the first wave is labeled C. A bracket labeled D connects the
Likurg_2 [28]

Answer:Label the parts of this wave.

A:  

✔ crest

B:  

✔ amplitude

C:  

✔ trough

D:  

✔ wavelength

Explanation:

8 0
2 years ago
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What is the balanced form of the chemical equation shown below?
Svetradugi [14.3K]

Answer:

D

Explanation:

Double Displacement reaction

Both sides are balanced with option D

3 0
3 years ago
The density of a 3.37M MgCl2 (FW = 95.21) is 1.25 g/mL. Calulate the molality, mass/mass percent, and mass/volume percent. So fa
Dafna1 [17]

Answer : The molality, mass/mass percent, and mass/volume percent are, 0.0381 mole/Kg, 25.67 % and 32.086 % respectively.

Solution : Given,

Density of solution = 1.25 g/ml

Molar mass of MgCl_2 (solute) = 95.21 g/mole

3.37 M magnesium chloride means that 3.37 gram of magnesium chloride is present in 1 liter of solution.

The volume of solution = 1 L = 1000 ml

Mass of MgCl_2 (solute) = 3.37 g

First we have to calculate the mass of solute.

\text{Mass of }MgCl_2=\text{Moles of }MgCl_2\times \text{Molar mass of }MgCl_2

\text{Mass of }MgCl_2=3.37mole\times 95.21g/mole=320.86g

Now we have to calculate the mass of solution.

\text{Mass of solution}=\text{Density of solution}\times \text{Volume of solution}=1.25g/ml\times 1000ml=1250g

Mass of solvent = Mass of solution - Mass of solute = 1250 - 320.86 = 929.14 g

Now we have to calculate the molality of the solution.

Molality=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Mass of solvent}}=\frac{3.37g\times 1000}{95.21g/mole\times 929.14g}=0.0381mole/Kg

The molality of the solution is, 0.0381 mole/Kg.

Now we have to calculate the mass/mass percent.

\text{Mass by mass percent}=\frac{\text{Mass of solute}}{\text{Mass of solution}}\times 100=\frac{320.86}{1250}\times 100=25.67\%

The mass/mass percent is, 25.67 %

Now we have to calculate the mass/volume percent.

\text{Mass by volume percent}=\frac{\text{Mass of solute}}{\text{Volume of solution}}\times 100=\frac{320.86}{1000}\times 100=32.086\%

The mass/volume percent is, 32.086 %

Therefore, the molality, mass/mass percent, and mass/volume percent are, 0.0381 mole/Kg, 25.67 % and 32.086 % respectively.

8 0
3 years ago
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