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Aleonysh [2.5K]

4 years ago

9

Answer this math question

2 answers:

Ede4ka [16]4 years ago

6 0

Answer:

<h3>arcYZ = 142</h3>

Step-by-step explanation:

const2013 [10]4 years ago

3 0

M∠YVZ = 90°

The measure of the angle formed by 2 chords that intersect inside the circle is 1/2<span> the sum of the chords' intercepted arcs.

(arcYZ+38)/2 = 90
arcYZ + 38 = 90*2
</span>arcYZ + 38 = 180
arcYZ = 180 - 38
arcYZ = 142°

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How many solutions are there to the equation below?

skad [1K]

Answer:

A. Infinitely many

Step-by-step explanation:

9x + 27 = 9(x + 2) + 9

Distribute on the right side.

9x + 27 = 9x + 18 + 9

Combine like terms on the right side.

9x + 27 = 9x + 27

Subtract 27 from both sides.

9x = 9x

Divide both sides by 9.

x = x

x = x is a true statement for every value of x. Therefore, any value you substitute in for x will make the original equation true. That means there is a infinite number of solutions.

Answer: A. Infinitely many

7 0

3 years ago

Simplify<br> (4^7/5^2)^3

oksano4ka [1.4K]

Answer:

655.36^3, or 281474976.711

Step-by-step explanation:

4 to the power of seven equals 16384.

5 to the power of two equals 25.

3 0

3 years ago

If a substance decays at a rate of 25% every 10 years, how long will it take 512 grams of the substance to decay to 121.5 grams

Juliette [100K]

Answer:

It will take 50 years to decay from 512 grams to 121.5 grams.

Step-by-step explanation:

The decay formula :

$N=N_0e^{-\lambda t}$

where

N= amount of substance after t time

N₀= initial of substance

t= time.

A substance decays at a rate 25% every 10 years.

So, remaining amount of the substance is = (100%-25%)= 75%

$\frac{N}{N_0}=\frac{75\%}{100\%}=\frac{75}{100}=\frac34$ , t= 10

$N=N_0e^{-\lambda t}$

$\Rightarrow \frac {N}{N_0}=e^{-\lambda t}$

$\Rightarrow \frac34 =e^{-\lambda .10}$

Taking ln both sides

$\Rightarrow ln|\frac34| =ln|e^{-\lambda .10}|$

$\Rightarrow ln|\frac34|=-10\lambda$

$\Rightarrow \lambda=\frac{ ln|\frac34|}{-10}$

Now , N₀= 512 grams, N= 121.5 grams, t=?

$N=N_0e^{-\lambda t}$

$\therefore 121.5=512e^{-\frac{ln|\frac34|}{-10}.t}$

$\Rightarrow 121.5=512e^{\frac{ln|\frac34|}{10}.t}$

$\Rightarrow \frac{121.5}{512}=e^{\frac{ln|\frac34|}{10}.t}$

Taking ln both sides

$\Rightarrow ln|\frac{121.5}{512}|=ln|e^{\frac{ln|\frac34|}{10}.t}|$

$\Rightarrow ln|\frac{121.5}{512}|={\frac{ln|\frac34|}{10}.t}$

$\Rightarrow t=\frac{ln|\frac{121.5}{512}|}{\frac{ln|\frac34|}{10}}$

$\Rightarrow t=\frac{10.ln|\frac{121.5}{512}|}{{ln|\frac34|}}$

⇒t=50 years

It will take 50 years to decay from 512 grams to 121.5 grams.

8 0

4 years ago

Please solve and hurryy!!!

natima [27]

Your answer is 137/150

Hope this helps

5 0

3 years ago

I need help, arithmetic sequences always mess me up

Jlenok [28]

Answer:

$a_{45}=399$ is the required term.

Step-by-step explanation:

We have been given an arithmetic sequence where we have a common difference which is: $d=a_2-a_1$

$d=12-3=9$

We will use the formula to find the required term:

$a_n=a+(n-1)d$

where, a is first term which is 3 and d is the common difference which is 9

and n =45 which we require to find.

$a_{45}=3+(45-1)(9)$

$a_{45}=3+396$

$a_{45}=399$ .

7 0

3 years ago

Read 2 more answers