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Sergeu [11.5K]
3 years ago
12

3.Last year, the numbers of skateboards produced per day at a certain factory were normally distributed with a mean of 20,500 sk

ateboards and a standard deviation of 55 skateboards.
(b) On what percent of the days last year did the factory produce 20,610 skateboards or more?
(c)On what percent of the days last year did the factory produce 20,445 skateboards or fewer?
Mathematics
1 answer:
TEA [102]3 years ago
7 0
Let X denote the number of skateboards produced daily.

\mathbb P(X\ge20610)=\mathbb P\left(\dfrac{X-20500}{55}\ge\dfrac{20610-20500}{55}\right)=\mathbb P(Z\ge2)\approx0.0228=2.28\%

\mathbb P(X\le20445)=\mathbb P(\left(\dfrac{X-20500}{55}\le\dfrac{20445-20600}{55}\right)=\mathbb P(Z\le-2.818)\approx0.00242=0.242\%
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8 0
3 years ago
Please help! Will give branliest for correct answer ! <br> God Bless uu!!
mafiozo [28]

Answer:

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3 years ago
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Hey there!

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We multiply .26 by o because o is how many oranges he bought and that's what we're solving for- so we multiply by the unit price.

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