keeping in mind that when the logarithm base is omitted, the base 10 is assumed.
![\textit{exponential form of a logarithm} \\\\ \log_a(b)=y \qquad \implies \qquad a^y= b \\\\[-0.35em] ~\dotfill\\\\ \log(x)=2\implies \log_{10}(x)=2\implies 10^2=x\implies 100=x](https://tex.z-dn.net/?f=%5Ctextit%7Bexponential%20form%20of%20a%20logarithm%7D%20%5C%5C%5C%5C%20%5Clog_a%28b%29%3Dy%20%5Cqquad%20%5Cimplies%20%5Cqquad%20a%5Ey%3D%20b%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Clog%28x%29%3D2%5Cimplies%20%5Clog_%7B10%7D%28x%29%3D2%5Cimplies%2010%5E2%3Dx%5Cimplies%20100%3Dx)
Answer:
Step-by-step explanation: In graphing there are two letters x, and y also called X-axis and Y-axis. They are called ordered pairs. To graph on the bottom of the graph are numbers 1-10 or more, those are X. At the left is a straight line numbers 1-10 or more. Now to actually graph if you get an ordered pair lets say, 3,4. the number on the left is the X, and the number on the right is the Y. There is an end in the X-axis, and Y-axis. Start from there, you will always start at the bottom then the left. Start at the 0,0 go three times to left at the bottom, then at the left go up four times. when you get 3,4 add a dot. Then that's your answer. It pretty easy. Hope it helps you!
Answer:
Its the last option. M and N are similar but not congruent.
Step-by-step explanation:
They have the same shape but are a different size.
2 1/2 = 2.5
12 1/2 = 12.5
This means you can calculate how may times it goes in by dividing it and rounding the number down:
12.5 / 2.5 = 5
*5 can not be rounded down so it stays the same
This means that 2 1/2 goes into 12 1/2 5 times. Hope this helps! :)
Ok let’s solve it
5(x-2)^2-20=0
first let’s foil (x-2)
5(x^2-4x+4) -20=0
now distribute the 5
5x^2 -20x +20 -20 = 0
combine like terms
5x^2-20x=0
take the gcf
5x(x-4)=0
x=0, 4
solutions are (4,0) and (2, -20) because the original vertex form a(x-h)^2+k
