Answer:
Since the pvalue of the test is 0.2743 > 0.1, the threshold probably was met.
Step-by-step explanation:
The widget manufacturing company had established a threshold of 60% preferring the proposed new widget to move forward with producing the new widgets.
This means that at the null hypothesis we test if the proportion is at least 60%, that is:

And the alternate hypothesis is:

The test statistic is:

In which X is the sample mean,
is the value tested at the null hypothesis,
is the standard deviation and n is the size of the sample.
0.6 is tested at the null hypothesis:
This means that:


Three hundred thirty-eight of 575 respondents reported preferring the proposed new widget.
This means that 
Value of the test-statistic:



Pvalue of the test and decision:
We want to find the probability of a proportion of 0.5878 or lower, which is the pvalue of z = -0.6.
Looking at the z-table, z = -0.6 has a pvalue of 0.2743.
Since 0.2743 > 0.1, the threshold probably was met.