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3 years ago

7

What is the greatest common factor for 26rs and 30r^5s^6

1 answer:

LenaWriter [7]3 years ago

4 0

Hello :
<span>the greatest common factor for 26rs and 30r^5s^6 is : 2rs</span>

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Please help with this problem.

Sergio039 [100]

The answer will be 14.93

3 0

4 years ago

Peter rides a bike along a triangular path in the neighborhood park. The sides of the path measure 3.36 miles, 4.18 miles, and 5

Molodets [167]

Answer:

The distance that Peter rides is:

<u>13.15 miles.</u>

Step-by-step explanation:

To identify the miles that Peter rides, you must imagine the triangle with measures: 3.36 miles, 4.18 miles, and 5.61 miles. How you can suppose, Peter regularly rides exactly by each side of the triangle mentioned, then you must find the perimeter of the triangle to identify the miles that Peter rides, remember that the perimeter of an irregular triangle is:

Perimeter of a triangle = side + side + side

If you replace the formula, you obtain:

Perimeter of a triangle = 3.36 miles + 4.18 miles + 5.61 miles
<u>Perimeter of a triangle = 13.15 miles</u>

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3 years ago

What is the total amount that Mathews bank will receive after lending him 8000 for four years

marysya [2.9K]

Answer:

32,000

Step-by-step explanation:

5 0

3 years ago

Plz help first right gets brainly

Anestetic [448]

A. Is not linear because is has no y
How this helped ya out! :D

6 0

3 years ago

Read 2 more answers

(Small sample confidence intervals for a population mean) suppose you are taking a sampling of 15 measurements. you find that x=

Luda [366]

Answer:

The 99% confidence interval is $71.67 < \mu < 78.33$

Step-by-step explanation:

From the question we are told that

The sample size is $n = 15$

The sample mean is $\= x = 75$

The standard deviation is $s = 5$

Given that confidence is 99% then the level of significance is mathematically represented as

$\alpha = 100 - 99$

$\alpha = 1\%$

$\alpha = 0.01$

Next we obtain the critical values of $\frac{ \alpha }{2}$ from the normal distribution table

The value is

$Z_{\frac{ \alpha }{2} } = 2.58$

Generally the margin for error is mathematically represented as

$E = Z_{\frac{ \alpha }{2} } * \frac{ s}{ \sqrt{n} }$

=> $E = 2.58 * \frac{ 5}{ \sqrt{15} }$

=> $E = 3.3307$

The 99% confidence interval is mathematically represented as

$\= x -E < \mu < \= x +E$

=> $75 - 3.3307 < \mu$

=> $71.67 < \mu < 78.33$

3 0

3 years ago