All categories

3 years ago

What are two things you will need to write an equation for a line?

Mathematics

1 answer:

vlabodo [156]3 years ago

3 0

Answer:

Slope and y intercept.

Step-by-step explanation:

This is necassary to write the equation of a line in y=mx+b

m is where the slope goes, and b is the y intercept.

Alternatively, you could also write the equation for a line with a point on the line and the slope.

You would then write it in point slope formula:

y-y1=m(x-x1)

This can later be converted into slope intercept form.

You might be interested in

What is the value of x in the equation 2 (x 3) = 4 (x minus 1)? 1 2 3 5.

nordsb [41]

Answer:

-2

Step-by-step explanation:

8 0

2 years ago

Solve using the histograms. How many watermelons weigh more than any of the cantaloupes? A. 10 B. 14 C. 17 D. 21

AleksAgata [21]

The answer is B. 14.

6 0

3 years ago

What is -(1)<br>Please help me.

KatRina [158]

It Is Just -1.
The Parenthesis Are All Simplified, And The Subtraction Sign Changes It To Negative. So, 1 Changed To Negative Is -1. <span />

8 0

3 years ago

PLEASE HELP FOR TEST will mark brainiest !!

sdas [7]

Answer:

552.920307 yd^2 or 552.92 yd^2 for sigfigs

Step-by-step explanation:

basically you take the area of the entire circle and subtract the interior circle to leave the ring and that’s your answer

so the area formula of a circle is π r^2

the radius (r) is just half the diameter so the entire diameter is 48 so the radius is 24 - π(24)^2 = 1809.557368^2

then the interior circle’s diameter is 40 so the radius is 20 - π(20)^2 = 1256.637061^2

so now it’s just subtraction:

1809.557368 yd^2 - 1256.637061 yd^2 =
552.920307 yd^2 or 552.92 yd^2 for sigfigs

hope this helps :)

6 0

2 years ago

Read 2 more answers

The point P(7, −2) lies on the curve y = 2/(6 − x). (a) If Q is the point (x, 2/(6 − x)), use your calculator to find the slope

NARA [144]

Answer:

a) (i) $m = 2.22$ , (ii) $m = 2$ , (iii) $m = 2$ , (iv) $m = 2$ , (v) $m = 1.82$ , (vi) $m = 2$ , (vii) $m = 2$ , (viii) $m = 2$ ; b) $m \approx 2$ ; c) The equation of the tangent line to curve at P (7, -2) is $y = 2\cdot x + 12$ .

Step-by-step explanation:

a) The slope of the secant line PQ is represented by the following definition of slope:

$m = \frac{\Delta y}{\Delta x} = \frac{y_{Q}-y_{P}}{x_{Q}-x_{P}}$

(i) $x_{Q} = 6.9$ :

$y_{Q} =\frac{2}{6-6.9}$

$y_{Q} = -2.222$

$m = \frac{-2.222 + 2}{6.9-7}$

$m = 2.22$

(ii) $x_{Q} = 6.99$

$y_{Q} =\frac{2}{6-6.99}$

$y_{Q} = -2.020$

$m = \frac{-2.020 + 2}{6.99-7}$

$m = 2$

(iii) $x_{Q} = 6.999$

$y_{Q} =\frac{2}{6-6.999}$

$y_{Q} = -2.002$

$m = \frac{-2.002 + 2}{6.999-7}$

$m = 2$

(iv) $x_{Q} = 6.9999$

$y_{Q} =\frac{2}{6-6.9999}$

$y_{Q} = -2.0002$

$m = \frac{-2.0002 + 2}{6.9999-7}$

$m = 2$

(v) $x_{Q} = 7.1$

$y_{Q} =\frac{2}{6-7.1}$

$y_{Q} = -1.818$

$m = \frac{-1.818 + 2}{7.1-7}$

$m = 1.82$

(vi) $x_{Q} = 7.01$

$y_{Q} =\frac{2}{6-7.01}$

$y_{Q} = -1.980$

$m = \frac{-1.980 + 2}{7.01-7}$

$m = 2$

(vii) $x_{Q} = 7.001$

$y_{Q} =\frac{2}{6-7.001}$

$y_{Q} = -1.998$

$m = \frac{-1.998 + 2}{7.001-7}$

$m = 2$

(viii) $x_{Q} = 7.0001$

$y_{Q} =\frac{2}{6-7.0001}$

$y_{Q} = -1.9998$

$m = \frac{-1.9998 + 2}{7.0001-7}$

$m = 2$

b) The slope at P (7,-2) can be estimated by using the following average:

$m \approx \frac{f(6.9999)+f(7.0001)}{2}$

$m \approx \frac{2+2}{2}$

$m \approx 2$

The slope of the tangent line to the curve at P(7, -2) is 2.

c) The equation of the tangent line is a first-order polynomial with the following characteristics:

$y = m\cdot x + b$

Where:

$x$ - Independent variable.

$y$ - Depedent variable.

$m$ - Slope.

$b$ - x-Intercept.

The slope was found in point (b) (m = 2). Besides, the point of tangency (7,-2) is known and value of x-Intercept can be obtained after clearing the respective variable:

$-2 = 2 \cdot 7 + b$

$b = -2 + 14$

$b = 12$

The equation of the tangent line to curve at P (7, -2) is $y = 2\cdot x + 12$ .

7 0

3 years ago