Why is combustion of fuel necessary for heat engines to do work?

Chemistry

2 answers:

azamat3 years ago

6 0

Because during combustion reaction, heat energy is released and it's this energy that is converted to work

sweet-ann [11.9K]3 years ago

5 0

Answer:

The energy from fuel can only be used when it is in the form of thermal energy. The energy stored in the chemical bonds of fuel are converted to thermal energy when the fuel is burned.

Explanation:

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Iron has a density of 7.9 space straight g divided by cm cubed. How much mass is in a 10 space cm cubed sample of iron? Question

dezoksy [38]

Answer:

79 g

Explanation:

Density (d) of iron = 7.9 g/cm³

Volume of the iron (V) = 10 cm³

Mass of the iron (m) = ?

Solution:

Formula will be used

d = m/V

As we have to find mass so rearrange the above equation

m = dV . . . . . . . . . . . (1)

Put values in above equation 1

m = 7.9 g/cm³ x 10cm³

m = 79 g

So,

mass of iron = 79 g

6 0

3 years ago

Consider two flasks at 25 degree Celsius, one contains an ideal gas and the other contains the real gas SO3. Which statement reg

Strike441 [17]

Answer: Option (A) is the correct answer.

Explanation:

In real gases, there exists force of attraction between the molecules at low temperature and high pressure. This is because at low temperature there occurs a decrease in kinetic energy of gas molecules and high pressure causes the molecules to come closer to each other.

As a result, forces of attraction increases as molecules come closer to each other and therefore, gases deviate from an ideal gas behavior.

And, at low pressure and high temperature there exists no force of attraction or repulsion between the molecules of a gas because they have high kinetic energy. Hence, gases behave ideally at these conditions.

Thus, we can conclude that the statement as the temperature approaches 0 K, the volume of the ideal gas will be larger than the volume of $SO_{3}$ because ideal gases lack inter-molecular forces, is true.

3 0

2 years ago

The molarity of a sodium hydroxide (NaOH) solution is 0.2 M. The molar mass of NaOH is 40 g/mol. If the solution contains 20 g o

mote1985 [20]

Answer:

$\large \boxed{\text{2.5 L}}$

Explanation:

1. Calculate the moles of NaOH.

$\text{Moles} = \text{20 g} \times \dfrac{\text{1 mol}}{\text{40 g}} = \text{0.50 mol}$

2. Calculate the volume of NaOH

$\begin{array}{rcl}\\\text{Molar concentration} &= &\dfrac{\text{moles}}{\text{litres}}\\\\ n &= &\dfrac{c}{V}\\\\\dfrac{\text{0.2 mol}}{\text{1 L}} &=& \dfrac{\text{0.50 mol}}{V}\\\\ \dfrac{0.2V}{\text{1 L}} & = & 0.50\\\\0.2V &= & \text{0.50 L}\\V & = & \dfrac{\text{0.50 L}}{0.2}\\\\& = & \textbf{2.5 L}\\\end{array}\\\text{The volume of the solution is $\large \boxed{\textbf{2.5 L}}$}$