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Zinaida [17]
3 years ago
8

Why is combustion of fuel necessary for heat engines to do work?

Chemistry
2 answers:
azamat3 years ago
6 0

Because during combustion reaction, heat energy is released and it's this energy that is converted to work

sweet-ann [11.9K]3 years ago
5 0

Answer:

The energy from fuel can only be used when it is in the form of thermal energy. The energy stored in the chemical bonds of fuel are converted to thermal energy when the fuel is burned.

Explanation:

You might be interested in
The kinetic molecular theory (KMT) deals specifically with
fgiga [73]
This kind of questions cannot be open because there might be many different answers depending of the focus.

In fact, I found the set of options that comes with this questions. This is:

A. behavior of ions.
B. molecular bonding.
C. molecular shape.
D. molecular motion.

Of course, the answer is the option D. molecular motion.

And, of course, you need an explanation.

It is good to know that the word kinetic refers to motion, so definetly kinetic molecular theory is a theory about the motion of the molecules.

With that you likely had been able to answer the question. But it is good to know what the molecular theory is.

The molecular kinetic molecular theory explains the properties and behavior of the gases in terms of the motion of its particles (molecules) making several assumptions about the energy, size and motion of such particles.
7 0
3 years ago
Read 2 more answers
The mode of 12, 17, 16, 14, 13, 16, 11, 14,13, 16 is​
RUDIKE [14]

Answer:

<h2>Mean = 14.2</h2><h2>Median = 14</h2><h2>Mode = 16</h2><h2>Range = 6</h2>

Explanation:

__________________________________________________________

<em>Mean = 14.2 or 14</em>

<em>Median = 14</em>

<em>Mode = 16</em>

<em>Range = 6</em>

<em>__________________________________________________________</em>

<em>Here are all the numbers from least to greatest order: 11, 12, 13, 13, 14, 14, 16, 16, 16, 17.</em>

<em>__________________________________________________________</em>

<em>Hope this helps! <3</em>

<em>__________________________________________________________</em>

8 0
3 years ago
Unknown element x is a metal that ionically bonds to sulfur.is the formula, x3s feasible? why or why not?a)it is feasible. the t
nasty-shy [4]
The correct answer is:
d) No, it is not feasible. three metallic ions cannot provide the exact number of electrons that one sulfur needs for the ionic bond.
Because Sulfur is divalent so it need to gain 2 electrons from metal so if we have 3 metals they can't provide only two electrons only.
8 0
3 years ago
Read 2 more answers
If a piece of cadmium with a mass of 37.60 g and a temperature of 100.0 oC is dropped into 25.00 cc of water at 23.0 oC, what wi
zlopas [31]

Answer:

T_{eq}=28.9\°C

Explanation:

Hello!

In this case, since it is observed that hot cadmium is placed in cold water, we can infer that the heat released due to the cooling of cadmium is gained by the water and therefore we can write:

Q_{Cd}+Q_{W}=0

Thus, we insert mass, specific heat and temperatures to obtain:

m_{Cd}C_{Cd}(T_{eq}-T_{Cd})+m_{W}C_{W}(T_{eq}-T_{W})=0

In such a way, since the specific heat of cadmium and water are respectively 0.232 and 4.184 J/(g °C), we can solve for the equilibrium temperature (the final one) as shown below:

T_{eq}=\frac{m_{Cd}C_{Cd}T_{Cd}+m_{W}C_{W}T_{W}}{m_{Cd}C_{Cd}+m_{W}C_{W}}

Now, we plug in to obtain:

T_{eq}=\frac{37.60g*0.232\frac{J}{g\°C}*100.00\°C+25.00g*4.184\frac{J}{g\°C}*23.0\°C}{37.60g*0.232\frac{J}{g\°C}+25.00g*4.184\frac{J}{g\°C}}\\\\T_{eq}=28.9\°C

NOTE: since the density of water is 1g/cc, we infer that 25.00 cc equals 25.00 g.

Best regards!

6 0
2 years ago
The diagram below show an enlarged view of the beams of a triple-beam balance
VLD [36.1K]

Answer:

1) 455.2 g. 2) 545.2 g.

Explanation:

i think this is right

6 0
3 years ago
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