<span>Mass of nitrogen = 14.0067
</span>
Mass of oxygen = 15.9994
In this compound nitrogen = 36.86 /
14.0067 = 2.63
<span>And oxygen = 63.14 / 15.9994 = 3.95 <span>
now we have: N----- 2.63 and O----3.95
by dividing both with the smallest number we get
</span></span>
<span>N-------2.63/2.63 = 1<span>
<span>O-------3.95/2.63 = 1.5
To get whole numbers we multiply both by 2
</span></span></span>
N= 1 x 2 = 2
And O = 1.5 x 2= 3
<span>So, the empirical formula is N</span>₂O₃.
Answer:
The answer will be A
Explanation:
I will send a photo with it
Metals are elements that are generally shiny when smooth and clean
Answer:
D
Explanation:I alredy know this i am in 7th gread
