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Sidana [21]
3 years ago
15

Use standard enthalpies of formation to calculate ΔH∘rxn for the following reaction______.2H2S(g)+3O2(g)→2H2O(l)+2SO2(g) ΔH∘rxn

=
Chemistry
1 answer:
Ahat [919]3 years ago
6 0

Answer:

-1,103.39KJ/mol

Explanation:

We use the subtract the standard enthalphies of formation of the reactants from that of the products. It must be taken into consideration that the enthalpy of formation of elements and their molecules alone are not taken into consideration. Hence, what we would be considering are the standard enthalpies of formation of H2S, H2O and SO2.

In places where we have more than one mole, we multiply by the number of moles as seen in the balanced chemical equations.

The standard enthalpies of the molecules above are as follows:

H2S = -20.63KJ/mol

H2O = -285.8KJ/mol

SO2 = -296.84KJ/mol

O2 = 0KJ/mol

ΔrH⦵ = [2ΔfH⦵(H2O) + 2 ΔfH⦵(SO2)] − [ΔfH⦵(H2S) + 3

 ΔfH⦵(O2)]

ΔrH⦵ =[(2 × -285.8) + (2 × -296.84)]

-[ 3 × -20.63)]

= (-571.6 - 593.68 + 61.89) = -1,103.39KJ/mol

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3mL of cyclohexanol (density = 0.9624 g/mL, Molecular weight = 100.158 g/mol) reacts with excess sulfuric acid to produce cycloh
TiliK225 [7]

Answer:

n_{C_6H_{10}}=0.03molC_6H_{10}

Explanation:

Hello,

In this case the undergoing chemical reaction is shown on the attached picture whereas cyclohexanol is converted into cyclohexene and water by the dehydrating effect of the sulfuric acid. Thus, for the starting 3 mL of cyclohexanol, the following stoichiometric proportional factor is applied in order to find the theoretical yield of cyclohexene in moles:

n_{C_6H_{10}}=3mLC_6H_{12}O*\frac{0.9624gC_6H_{12}O}{1mLC_6H_{12}O}*\frac{1molC_6H_{12}O}{100.158gC_6H_{12}O}*\frac{1molC_6H_{10}}{1molC_6H_{12}O} \\n_{C_6H_{10}}=0.03molC_6H_{10}

Besides, the mass could be computed as well by using the molar mass of cyclohexene:

m_{C_6H_{10}}=0.03molC_6H_{10}*\frac{82.143gC_6H_{10}}{1molC_6H_{10}} \\\\m_{C_6H_{10}}=2.4gC_6H_{10}

Even thought, the volume could be also computed by using its density:

V_{C_6H_{10}}=2.4gC_6H_{10}*\frac{1mLC_6H_{10}}{0.811gC_6H_{10}} \\V_{C_6H_{10}}=3mLC_6H_{10}

Best regards.

4 0
3 years ago
Read 2 more answers
1) How much energy would be required to melt 15.0 g of ice at 0°C?
DerKrebs [107]

Answer:

5010J

Explanation:

The following data were obtained from the question:

Mass (m) = 15g

Heat of fusion (ΔHf) = 334J/g

Heat required (Q) =..?

The heat energy required to melt the ice can be obtained as follow:

Q = m·ΔHf

Q = 15 x 334

Q = 5010J

Therefore, the heat energy required to melt the ice is 5010J.

8 0
3 years ago
Choose the statement below that is TRUE. A weak acid solution consists of mostly insoluble acid molecules. The term 'strong elec
lora16 [44]

Answer: Option (A) is the correct answer.

Explanation:

A weak acid is defined as a substance which dissociates partially into a solvent. This also means that most of the molecules of a weak acid solution remain insoluble in nature.

A solution in which solute particles completely dissociate into ions in a solvent is known as a strong electrolyte.

Whereas a solution in which solute particles partially dissociate into ions is known as a weak electrolyte.

A molecular compound is a covalent compound and as like dissolves like. So, molecular compounds are not soluble in polar solvent like water.

Therefore, we can conclude that the true statement is weak acid solution consists of mostly insoluble acid molecules.

5 0
3 years ago
Where on the periodic table are the majority of radioactive isotopes found?
Oliga [24]
Periodic table is an arrangement of chemical elements in an organized manner with atomic number. Elements are distributed in columns and groups in periodic table according to their properties.
Many elements have their isotopes and mostly are radioactive but isotopes are not mentioned on the periodic table, elements are mentioned there and all trans-uranium elements are most radioactive.
5 0
3 years ago
Write the names of the following covalent compounds: no2
Nuetrik [128]

Answer:

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Explanation:

this was on my chemistry test

7 0
3 years ago
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