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RideAnS [48]
3 years ago
15

How many mL of 3.0M HCl are needed to make 300.0 mL of a 0.10M HCl?

Chemistry
1 answer:
nalin [4]3 years ago
3 0

Answer:

V₁  = 10 mL

Explanation:

Given data:

Initial volume of HCl = ?

Initial molarity = 3.0 M

Final molarity = 0.10 M

Final volume = 300.0 mL

Solution:

Formula:

M₁V₁  =  M₂V₂

M₁ = Initial molarity

V₁  =  Initial volume of HCl

M₂ =Final molarity

V₂ = Final volume

Now we will put the values.

3.0 M ×V₁  =  0.10 M×300.0 mL

3.0 M ×V₁  = 30 M.mL

V₁  = 30 M.mL /3.0 M

V₁  = 10 mL

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so   the empirical (lowest raios) is

C2H4Cl      

                                 

                               

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