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3 years ago

How many mL of 3.0M HCl are needed to make 300.0 mL of a 0.10M HCl?

Chemistry

1 answer:

nalin [4]3 years ago

3 0

Answer:

V₁ = 10 mL

Explanation:

Given data:

Initial volume of HCl = ?

Initial molarity = 3.0 M

Final molarity = 0.10 M

Final volume = 300.0 mL

Solution:

Formula:

M₁V₁ = M₂V₂

M₁ = Initial molarity

V₁ = Initial volume of HCl

M₂ =Final molarity

V₂ = Final volume

Now we will put the values.

3.0 M ×V₁ = 0.10 M×300.0 mL

3.0 M ×V₁ = 30 M.mL

V₁ = 30 M.mL /3.0 M

V₁ = 10 mL

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