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VMariaS [17]
3 years ago
12

What is the formula for surface area

Mathematics
2 answers:
zubka84 [21]3 years ago
6 0
The area is perimeter times height plus area of the bases
lorasvet [3.4K]3 years ago
3 0
Lw+lw+hl+hl+hw+hw. Is the anwser I think but I think i am wrong though
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a nursery owner buys 5 panes cost $14.25. unfortunately, she breaks 2 more panes while reparing the damage. what is the cost of
miskamm [114]

Divide the total cost by all 5 panes to get the cost of 1 pane:

14.25/5 = 2.85

Then multiply by 2:

2.85 * 2 = $5.7

8 0
3 years ago
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Karen and Tom sold candy bars for a fundraiser, Karen sold 7 less than twice the number of candy
Eddi Din [679]

Answer:

89

Step-by-step explanation:

7 0
3 years ago
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Please show your work
coldgirl [10]

Answer:

m(h+p) - p÷h + m

h = -1, m = 3, and p = 4

3(-1+4) - 4÷(-1) + 3

= 3(3) - (-4) + 3

= 9 + 4 + 3

= 16

D. 16

7 0
3 years ago
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car prices are projected to increase by 125% in 10 years. now a car cost $2000. What is the projected cost in 10 years?
KATRIN_1 [288]

Answer:

Step-by-step explanation:

punanni

8 0
3 years ago
A random sample of 49 measurements from one population had a sample mean of 15, with sample standard deviation 5. An independent
kotykmax [81]

Answer:

Comparing the p value with the significance level \alpha=0.01 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and the difference between the two groups is significantly different.  

Step-by-step explanation:

\bar X_{1}=15 represent the mean for sample 1

\bar X_{2}=18 represent the mean for sample 2

s_{1}=5 represent the sample standard deviation for 1  

s_{f}=6 represent the sample standard deviation for 2  

n_{1}=49 sample size for the group 2  

n_{2}=64 sample size for the group 2  

\alpha=0.01 Significance level provided

t would represent the statistic (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to check if the difference in the population means, the system of hypothesis would be:  

Null hypothesis:\mu_{1}-\mu_{2}=0  

Alternative hypothesis:\mu_{1} - \mu_{2}\neq 0  

We don't have the population standard deviation's, so for this case is better apply a t test to compare means, and the statistic is given by:  

t=\frac{(\bar X_{1}-\bar X_{2})-\Delta}{\sqrt{\frac{s^2_{1}}{n_{1}}+\frac{s^2_{2}}{n_{2}}}} (1)

And the degrees of freedom are given by df=n_1 +n_2 -2=49+64-2=111  

t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

With the info given we can replace in formula (1) like this:  

t=\frac{(15-18)-0}{\sqrt{\frac{5^2}{49}+\frac{6^2}{64}}}}=-2.897

P value

Since is a bilateral test the p value would be:  

p_v =2*P(t_{111}  

Comparing the p value with the significance level \alpha=0.01 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and the difference between the two groups is significantly different.  

7 0
3 years ago
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