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brilliants [131]
3 years ago
13

Can you help me with the 3 questions

Mathematics
1 answer:
iren [92.7K]3 years ago
8 0

Answer:

5

Step-by-step explanation:

44444444444444444444444555555555555555555555555444444454444444444444444444

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Solve for x t=1/2(1/x-1/y)
Ilya [14]

Answer:

Step-by-step explanation:

671518 jnaja(a iuyquq uhh 71718(2961881

8 0
3 years ago
What digit can be in the ones place of a number that has 5 as a factor
saveliy_v [14]
Only numbers possible would be five and zero

8 0
3 years ago
How can you graph m(x)=5x and then compare it to f(x)=x?
erastovalidia [21]
Graph the line y=5x. Then graph the line y=x. Then look at them and describe in what ways they are the same or different.
5 0
3 years ago
Can any one here please help me in this math problem I really need help
MArishka [77]

Answer:

The volume of the solid is the volume of the prism minus the volume of the cylinder.

For the cylinder, diameter = d = 4 cm

radius = d/2 = (4 cm)/2 = 2 cm

V = volume of prism - volume of cylinder

The volume of a prism is length times width times height.

The volume of a cylinder is pi times the square of the radius times the height.

V = LWH - (pi)r^2h

V = 6 cm * 6 cm * 15 cm - (pi)(2 cm)^2(15 cm)

V = 540 cm^3 - 60pi cm^3

V = (540 - 60pi) cm^3

5 0
3 years ago
A shipment of 11 printers contains 2 that are defective. Find the probability that a sample of size 2​, drawn from the 11​, will
svet-max [94.6K]

The required probability is \frac{36}{55}

<u>Solution:</u>

Given, a shipment of 11 printers contains 2 that are defective.  

We have to find the probability that a sample of size 2, drawn from the 11, will not contain a defective printer.

Now, we know that, \text { probability }=\frac{\text { favourable outcomes }}{\text { total outcomes }}

Probability for first draw to be non-defective =\frac{11-2}{11}=\frac{9}{11}

(total printers = 11; total defective printers = 2)

Probability for second draw to be non defective =\frac{10-2}{10}=\frac{8}{10}=\frac{4}{5}

(printers after first slot = 10; total defective printers = 2)

Then, total probability =\frac{9}{11} \times \frac{4}{5}=\frac{36}{55}

7 0
3 years ago
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