Answer:
No solution
Step-by-step explanation:
Given: 
and 
Solve both inequality separately.
Subtraction property of inequality
and
Addition property of inequality
Hence, the solution of the compound inequality intersection of both solutions.
Please find attachment for number line solution.
No solution
Answer:
w = ±![\sqrt[4]{36/5}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B36%2F5%7D)
Step-by-step explanation:
-8+5w^4=28
You can regroup it:
5w^4 - 8 = 28
Add 8 to both side:
5w^4 = 28 + 8
5w^4 = 36
Divide both side by 5:
5w^4/5 = 36/5
w^4 = 36/5
Take the 4 root of both sides:
w = ±
Hope this help you :3
Answer:
m < amc = 54°
Step-by-step explanation:
< amb and < bmc are complementary angles whose sum equals 90°.
Therefore, to find the value of 2x°, we must first solve for x.
We can establish the following equality statement:
< amb + < bmc = < amc
< 2x° + (x + 9)° = 90°
Combine like terms:
2x° + x° + 9° = 90°
3x° + 9° = 90°
Subtract 9 from both sides:
3x° + 9° - 9° = 90° - 9°
3x = 81°
Divide both sides by 3 to solve for x:
3x/3 = 81°/3
x = 27°.
Since x = 27°, substitute its value into 2x° to find m < amc:
2x° = 2(27°) = 54°
Therefore, m < amc = 54°
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20 tulips. 2/3=20/30 when you multiply both the denominator and numerator by 10.
Tbe question doesn't state the number of days he walked to school out of 20 school days in the
Month of February.
Answer:
Kindly check explanation
Step-by-step explanation:
To. Obtain the fractional representayion for the number of days he walked to school ;
Let the number of days he walked to school = 10 (this is an hypothesized value)
Number of school days in February = 20
Fraction = 10 /20 = 0.5
The percentage of times walked to school : multiply the fraction obtained above by 100%
0.5 * 100% = 50%
Just put the desired value and proceed uSing the steps described above.
