All categories

3 years ago

Is 6(6+x) equivalent to 6x+36

Mathematics

2 answers:

Ray Of Light [21]3 years ago

5 0

Close enough, it would be 36+6x.

zysi [14]3 years ago

3 0

Answer:Yes

Step-by-step explanation:

For 6(6+x), you have to multiply what’s in the parentheses with 6. Multiply 6 and 6 first which gives you 36. Then multiply 6 and x which gives you 6x. Therefore, it’s simplified as 6x+36

You might be interested in

Sarah and George went on hiking trip over the weekend to Mt.Shasta. On Saturday they hiked 9/12 mile. On Saturday they hike 4/12

Citrus2011 [14]

It will be a difference of B. 5/12 miles

6 0

3 years ago

Help

SpyIntel [72]

Answer:

the admininstrative assistant can type 70 word in a minute i think

Step-by-step explanation:

5 0

2 years ago

PLEASEEEEEE AWNSER I NEED HELP! (AWNSER in scientific notation) 24-27

N76 [4]

Answer:

24 - 27 = -3

and if you meant 2/4 - 2/7 in scientic notation:

2/4 - 2/7 = 3/14

HOPE THIS HELPS

5 0

2 years ago

Please help me with the below question.

VMariaS [17]

By letting

$y = \displaystyle \sum_{n=0}^\infty c_n x^{n+r}$

we get derivatives

$y' = \displaystyle \sum_{n=0}^\infty (n+r) c_n x^{n+r-1}$

$y'' = \displaystyle \sum_{n=0}^\infty (n+r) (n+r-1) c_n x^{n+r-2}$

a) Substitute these into the differential equation. After a lot of simplification, the equation reduces to

$5r(r-1) c_0 x^{r-1} + \displaystyle \sum_{n=1}^\infty \bigg( (n+r+1) c_n + (n + r + 1) (5n + 5r + 1) c_{n+1} \bigg) x^{n+r} = 0$

Examine the lowest degree term $\left(x^{r-1}\right)$ , which gives rise to the indicial equation,

$5r (r - 1) + r = 0 \implies 5r^2 - 4r = r (5r - 4) = 0$

with roots at r = 0 and r = 4/5.

b) The recurrence for the coefficients $c_k$ is

$(k+r+1) c_k + (k + r + 1) (5k + 5r + 1) c_{k+1} = 0 \implies c_{k+1} = -\dfrac{c_k}{5k+5r+1}$

so that with r = 4/5, the coefficients are governed by

$c_{k+1} = -\dfrac{c_k}{5k+5} \implies \boxed{g(k) = -\dfrac1{5k+5}}$

c) Starting with $c_0=1$ , we find

$c_1 = -\dfrac{c_0}5 = -\dfrac15$

$c_2 = -\dfrac{c_1}{10} = \dfrac1{50}$

so that the first three terms of the solution are

$\displaystyle \sum_{n=0}^2 c_n x^{n + 4/5} = \boxed{x^{4/5} - \dfrac15 x^{9/5} + \frac1{50} x^{13/5}}$

4 0

2 years ago

Find the percent of increase or decrease from the first number to the second number. 140 to 84

tresset_1 [31]

We can automatically see that we are dealing with a percent decrease because we are going from a smaller to a bigger number. We need to first find what percent of 140the number 84 is. to do this we can set up the following equation:

140/84=100/x (this equation is basically saying if 140 is 100(%) what would 84 be?)

solving for x here gives us x = (84 X 100)/140 = 60, so 84 is 60 percent of 140 which means 140 decreased by 40 percent.

Let me know if I can clear anything else up.

8 0

2 years ago