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4 years ago

five criterion team bikes cost $ 11,300. How much would the club have to pay for a dozen criterion team bikes?

1 answer:

7 0

First of all divide 11,300 by 5 and get 2,260 which then multiply it by 12 which will get you 27,120 as the answer.

So it would cost $27,120 to get a dozen criterion team bikes.

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PLEASE HELP ITS DUE SOIN AND I DONT KNOW HOW TO ANSWER

KiRa [710]

Answer:

y = - 3

Step-by-step explanation:

Given the 2 equations

6x + 11y = - 3 → (1)

4x + y = = 17 → (2)

Multiplying (1) by 4 and (2) by - 6, then adding will eliminate the term in x

24x + 44y = - 12 → (3)

- 24x - 6y = - 102 → (4)

add (3) and (4) term by term to eliminate x

0 + 38y = - 114

38y = - 114 ( divide both sides by 38 )

y = - 3

8 0

3 years ago

Anyone know how to do this find the slope? Will give brainliest.

Molodets [167]

Explanation: In my notes you’ll see the formula for how to find slope under “Formulas”.

How to use this formula: In the first graph you have points (2,3) and (6,8)
So y2 would be 8, and y1 would be 3.
x2 would be 6, and x1 would be 2.

1. Sub points into formula
2. subtract y2 by y1
3. Subtract x2 by x1
4. Divide top by bottom

And you’ve got your slope! (Rise/run)

If you need further clarification, feel free to ask me in the comments. Hope this helps :)

3 0

3 years ago

Read 2 more answers

2.) Fill in the blank.

Montano1993 [528]

Answer:

E.) 1

Step-by-step explanation:

Firstly we will solve for L.H.S.

L.H.S. = $Csc^2\theta$

Since we know that $Csc^2\theta$ is the inverse of $Sin^2\theta$ .

So we can say that;

$csc^2\theta=\frac{1}{sin^2\theta}$

Now For R.H.S.

$Cot^2\theta+1$

Since we can rewrite $cot^2\theta$ as $\frac{cos^2\theta}{sin^2\theta}$ .

Now we can say that the R.H.S. is;

$\frac{cos^2\theta}{sin^2\theta}+1$

Now we add the fraction and get;

$\frac{cos^2\theta+sin^2\theta}{sin^2\theta}$

Now according to trigonometric identity;

$cos^2\theta+sin^2\theta=1$

So, $\frac{cos^2\theta+sin^2\theta}{sin^2\theta}=\frac{1}{sin^2\theta}$

Here,

$csc^2\theta=\frac{1}{sin^2\theta}$ and $Cot^2\theta+1$ = $\frac{1}{sin^2\theta}$ <em> </em>

L.H.S. = R.H.S.

Hence $csc^2\theta=cot^2\theta+1$

4 0

3 years ago

.......................

vlada-n [284]

Hey there! :D

Let's keep the fraction 5/7 in mind. We should be able to reduce everything to 5/7.

15:21 (divide both by 3) you get 5:7. That is equivalent.

10 to 14. Divide both by 2. 5 to 7. That is equivalent.

The correct answer is 28/20. That is not equivalent.

I hope this helps!
~kaikers

4 0

3 years ago

Graph the equation<br>y=x^2 -<br><img src="https://tex.z-dn.net/?f=y%20%3D%20x%5E%7B2%7D%20%20-%202" id="TexFormula1" title="y =

rusak2 [61]

Answer:

the graph is attached below

Step-by-step explanation:

$y=x^2 - 2$

LEts make a table to get the coordinates

we need to select integers between -3 and 3

x y=x^2 - 2

-2 y=(-2)^2-2=2 (-2,2)

0 y= (0)^2 - 2= -2 (0,-2)

2 y=(2)^2-2 = 2 (2,2)

Now we use the table for graphing the given equation

The graph is attached below

6 0

4 years ago