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2 years ago

five criterion team bikes cost $ 11,300. How much would the club have to pay for a dozen criterion team bikes?

1 answer:

7 0

First of all divide 11,300 by 5 and get 2,260 which then multiply it by 12 which will get you 27,120 as the answer.

So it would cost $27,120 to get a dozen criterion team bikes.

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A company administers an "aptitude test for managers" to aid in selecting new management trainees. Prior experience suggests tha

RoseWind [281]

Answer:

0.94

Step-by-step explanation:

The question after this basically is:

"If the applicant passes the "aptitude test for managers", what is the probability that the applicant will succeed in the management position?"

So,

P(successful if hired) = 60% = 0.6 [let it be P(x)]

P(success at passing the test) = 85% = 0.85 [let it be P(y)]

P(successful and pass the test) = P(x) + P(y) -[P(x)*P(y)]

So,

P(successful and pass the test) = 0.6 + 0.85 - (0.6*0.85) = 0.94 (94%)

5 0

2 years ago

PLEASE ANSWER ASAP FOR BRAINLEST SUPER EASY QUESTION!!!!!!!!!!!!!!!!!!!!

Zolol [24]

Answer:

you can find the height of a rectangular prism

3 0

2 years ago

Write the following set using roster notation. Do not include repeats.

Annette [7]

Answer:

Step-by-step explanation:C

4 0

2 years ago

Can someone please explain how to get the answer?

nydimaria [60]

The small triangle is 1/2 the size of the larger one ( comparing like sides 5 is 1/2 of 10).

This means AC is 1/2LN.

So you have:

x +5 = 1/2(3x +3)

Simplify:

x+5 = 1.5x +1.5

Subtract 1.5x from each side:

-.5x +5 = 1.5

Subtract 5 from each side:

-.5x = -3.5

Divide both sides by -.5:

x = -3.5 / -.5

x = 7

Now you have x.

AC = x +5 = 7+5 = 12

The answer is G.

6 0

2 years ago

(x sin a + y cos a)^2 + (x cos a – y sin a)^2 = x^2 + y^2

kobusy [5.1K]

Answer:

Proved

Step-by-step explanation:

Required

Prove that:

$(x\ sin\ a + y\ cos\ a)^2 + (x\ cos\ a - y\ sin\ a)^2 = x^2 + y^2$

Solving from left to right:

Open brackets

$(x\ sin\ a + y\ cos\ a)(x\ sin\ a + y\ cos\ a) + (x\ cos\ a - y\ sin\ a)(x\ cos\ a - y\ sin\ a) = x^2 + y^2$ $x^2\ sin^2 a + 2xy\ sin\ a\ cos\ a + y^2\ cos^2 a + x^2\ cos^2 a - 2xy\ sin\ a\ cos\ a + y^2\ sin^2 a = x^2 + y^2$