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miss Akunina [59]

4 years ago

10

five criterion team bikes cost $ 11,300. How much would the club have to pay for a dozen criterion team bikes?

1 answer:

Vadim26 [7]4 years ago

7 0

First of all divide 11,300 by 5 and get 2,260 which then multiply it by 12 which will get you 27,120 as the answer.

So it would cost $27,120 to get a dozen criterion team bikes.

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3 years ago

He truck is rented at $40 per day plus they charge per mile of use the truck travel 15 miles in one day and the total charge was

Allushta [10]

Answer:

$115 = 15 x + 40$

the charge is $5 dollars per mile

Step-by-step explanation:

He truck is rented at $40 per day plus they charge per mile of use the truck travel 15 miles in one day and the total charge was 115

LEt x be the charge in dollars per hour

Initial charge is 40 and 15 miles travelled in one day

total charge = 15x + 40

Given : total charge is 115

So the equation becomes

$115 = 15 x + 40$

Now we solve for x

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7 0

3 years ago

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In triangle ABC, a = 4, b =5, angle c = 110, find length of median to the longest side

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3 years ago

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scoundrel [369]

The y factors of the given quadratic equation is -1 and 40/22.

According to the statement

we have given that the equation and we have to find the factors of those equation.

So, The given equation is:

$Y =x^2-23x^2 + 18x+40$

where y is the factors of that equation.

So, we have to find the factors of the given quadratic equation.

$x^2-23x^2 + 18x+40 = 0$

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Then take negative sign common from it then

$22x^2 - 18x - 40 = 0$

Make the factors of this quadratic equation

$22x^2 + 22x -40x - 40 = 0$

Now take common values 22x and 40 from the equation then

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Then it become

$(22x - 40) (x + 1) = 0$

Then the values of x become from the equation is

$x = -1, x= 40/22$

The value of the factors y is -1 and 40/22.

So, The y factors of the given quadratic equation is -1 and 40/22.

Learn more about Quadratic equation here

brainly.com/question/24334139

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8 0

1 year ago